X^2-6x+1=0 solve by completing square

Mathematics

2 answers:

asambeis [7]2 years ago

8 0

Answer:

x = 3 ± 2 $\sqrt{2}$

Step-by-step explanation:

x² - 6x + 1 = 0 ( subtract 1 from both sides )

x² - 6x = - 1

to complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(- 3)x + 9 = - 1 + 9

(x - 3)² = 8 ( take square root of both sides )

x - 3 = ± $\sqrt{8}$ = ± 2 $\sqrt{2}$ ( add 3 to both sides )

x = 3 ± 2 $\sqrt{2}$

Harrizon [31]2 years ago

5 0

The answer is x= +- 2 square root of 2 + 3

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