3(2-b)<10-3(b-6)
6-b<5(b-6)
6-b<5b-30
Let's make "b".......2
6-(2)<5(2)-30
4<10-30
4<-20
In this case, this is a false statement. You can make "b" any number and I chose 2. I hope this helped!
3/2x-7=-11
We move all terms to the left:
3/2x-7-(-11)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
We add all the numbers together, and all the variables
3/2x+4=0
We multiply all the terms by the denominator
4*2x+3=0
Wy multiply elements
8x+3=0
We move all terms containing x to the left, all other terms to the right
8x=-3
x=-3/8
x=-3/8
Answer:
after 21 seconds
Step-by-step explanation:
Given
h = - 16t² + 272t + 1344
When the ball strikes the ground then h = 0, that is
- 16t² + 272t + 1344 = 0 ( divide through by - 16 )
t² - 17t - 84 = 0 ← in standard form
(t - 21)(t + 4) = 0 ← in factored form
Equate each factor to zero and solve for t
t - 21 = 0 ⇒ t = 21
t + 4 = 0 ⇒ t = - 4
However t > 0 thus t = 21
The ball strikes the ground after 21 seconds.
23. If M' represents the complementary, then is the answer A.
24. The answer is C.
Answer:
the answer is attached to the picture