Answer:
95% confidence interval for the variance of the bowling ball weight is between a lower limit of 13.328 pounds and an upper limit of 14.672 pounds.
Step-by-step explanation:
Confidence interval is given as weight +/- margin of error (E)
weight = 14 pounds
sample sd = 0.94 pound
n = 10
degree of freedom = n - 1 = 10 - 1 = 9
confidence level (C) = 95% = 0.95
significance level = 1 - C = 1 - 0.95 = 0.05 = 5%
critical value (t) corresponding to 9 degrees of freedom and 5% significance level is 2.262
E = t × sample sd/√n = 2.262×0.94/√10 = 0.672 pounds
Lower limit of weight = weight - E = 14 - 0.672 = 13.328 pounds
Upper limit of weight = weight + E = 14 + 0.672 = 14.672 pounds.
95% confidence interval is (13.328, 14.672)
Answer:
-6.5 would be your answer
Step-by-step explanation:
Answer:
Step-by-step explanation:
51 + 32 = 83 for DE
13 3/4 = ((13x4)+3)/4 = 55/4
1 2/3 = ((1x3)+2)/3 = 5/3
55/4 / 5/3
(55x3)/(5x4)
165/20
33/4
8 1/4
