The value of p = 11
y = 5x + p
1 = 5(-2) + p
1 = -10 + p
11 = p
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data:
(x - 4)² + y² = 16
Step 02:
polar form:
x = r cos (θ)
y = r sin (θ)
(r cos (θ) - 4 )² + (r sin (θ))² = 16
(r cos θ - 4)² + r² sin² θ = 16
r (r - 8 cos (θ)) = 0
r = 8 cos θ
The answer is:
r = 8 cos θ
We have two solutions for this problem based on the given equation.
<u><em>Answer #1:</em></u>
<u>If the given equation was:</u>

To solve for f, we would need to isolate the "f" on one side of the equation.
In case of the above equation, we can simply do that by subtracting
from both sides of the equation
<u>This would give:</u>
f +
-
= 6 - 
f = 6 - 
<u><em>Answer #2:</em></u>
<u>If the given equation was:</u>

To solve for f, we would still need to isolate the "f" on one side of the equation.
<u>This can be done as follows:</u>
................> multiply both sides by (g)
f + 4 = 6g ................> subtract 4 from both sides of the equation
f + 4 - 4 = 6g - 4
f = 6g - 4
Hope this helps :)
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