What is the surface area of this right prism? Enter your answer in the box. cm²
1 answer:
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Answer:
The standard deviation increased but there was no change in the interquantile range
Step-by-step explanation:
We are given the following data in the question:
320, 411, 348, 537, 420, 449, 462, 403, 454, 517, 515, 358, 438, 541, 387, 368, 502, 437, 431, 428.
n = 20
a) Formula:
where are data points,
is the mean and n is the number of observations.
Sum of squares of differences =
13525.69 + 640.09 + 7796.89 + 10140.49 + 265.69 + 161.29 + 660.49 + 1108.89 + 313.29 + 6512.49 + 6193.69 + 6130.89 + 2.89 + 10962.09 + 2430.49 + 4664.89 + 4316.49 + 0.49 + 28.09 + 68.89 = 75924.2
Sorted Data = 320, 348, 358, 368, 387, 403, 411, 420, 428, 431, 437, 438, 449, 454, 462, 502, 515, 517, 537, 541
IQR =
b) After changing the observation
0, 411, 348, 537, 420, 449, 462, 403, 454, 517, 515, 358, 438, 541, 387, 368, 502, 437, 431, 428
Sum of squares of differences =
176652.09 + 86.49 + 5227.29 + 13618.89 + 0.09 + 823.69 + 1738.89 + 299.29 + 1135.69 + 9350.89 + 8968.09 + 3881.29 + 313.29 + 14568.49 + 1108.89 + 2735.29 + 6674.89 + 278.89 + 114.49 + 59.29 = 247636.2
Sorted Data = 0, 348, 358, 368, 387, 403, 411, 420, 428, 431, 437, 438, 449, 454, 462, 502, 515, 517, 537, 541
IQR =
Thus. the standard deviation increased but there was no change in the interquantile range.
Answer:
Step-by-step explanation:
i believe this is the answer but i am not 100% sure
A.
(0,00
(2.6,7.9)
(4.8,12.4)
(9.7,15.1)
b.
well, the points don't look like they are on the line but they actually are (plot twist)
so
since (0,0) is on th egarph
0=a(0)²+b(0)+c
0=c
so
f(x)=ax²+bx+0 or
f(x)=ax²+bx
find a and b
sub points
(2.6,7.9)
7.9=a(2.6)²+b(2.6)
7.9=6.76a+2.6b
(4.8,12.4)
12.4=a(4.8)²+b(4.8)
12.4=23.04a+4.8b
use those 2 equations
7.9=6.76a+2.6b
12.4=23.04a+4.8b
eliminate b
multiply first equation by -4.8 and 2nd by 2.6 and add them
-37.92=-32.448a-12.48b
32.24=59.904a-12.48b +
-5.68=27.456a+0b
-5.68=27.456a
divide both sides by 27.456
(-5.68/27.456)=a
find b
12.4=23.04a+4.8b
12.4=(-130.8672/27.456)+4.8b
12.4+(130.8672/27.456)=4.8b
(12.4+(130.8672/27.456))/4.8=b
da equation is
c. the roots are found with your calculator
the roots are at x=0 and x=17.287323943662
so very close to the target but not exactly on it
if the target has a radius of 0.287323943662 or more then it will hit the target
(0,00
(2.6,7.9)
(4.8,12.4)
(9.7,15.1)
b.
well, the points don't look like they are on the line but they actually are (plot twist)
so
since (0,0) is on th egarph
0=a(0)²+b(0)+c
0=c
so
f(x)=ax²+bx+0 or
f(x)=ax²+bx
find a and b
sub points
(2.6,7.9)
7.9=a(2.6)²+b(2.6)
7.9=6.76a+2.6b
(4.8,12.4)
12.4=a(4.8)²+b(4.8)
12.4=23.04a+4.8b
use those 2 equations
7.9=6.76a+2.6b
12.4=23.04a+4.8b
eliminate b
multiply first equation by -4.8 and 2nd by 2.6 and add them
-37.92=-32.448a-12.48b
32.24=59.904a-12.48b +
-5.68=27.456a+0b
-5.68=27.456a
divide both sides by 27.456
(-5.68/27.456)=a
find b
12.4=23.04a+4.8b
12.4=(-130.8672/27.456)+4.8b
12.4+(130.8672/27.456)=4.8b
(12.4+(130.8672/27.456))/4.8=b
da equation is
c. the roots are found with your calculator
the roots are at x=0 and x=17.287323943662
so very close to the target but not exactly on it
if the target has a radius of 0.287323943662 or more then it will hit the target