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3 years ago

Please help. Thx!

Mathematics

1 answer:

makvit [3.9K]3 years ago

4 0

Answer:

use G

authmaths

Step-by-step explanation:

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On the map of an amusement park on a coordinate grid, the skating rink is at (−1.5, −1).

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Start at the origin. This is where the x and y axis meet
x axis = horizontal axis numberline
y axis = vertical axis numberline

From the origin, then move 1.5 units to the left. This is what it means when x is negative. We move that amount to the left.

The y coordinate is -1 so we move down 1 unit

Answer: Choice A

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4 years ago

What is the solution to the graph

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Point where lines intersect (-1,2)

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2 years ago

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DaniilM [7]

We know that

[the area of a circle]=pi*r²
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4 years ago

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An explosion causes debris to rise vertically with an initial speed of 120 feet per second. The formula h equals negative 16 t s

Novay_Z [31]

Answer:

The debris will be at a height of 56 ft when time is <u>0.5 s and 7 s.</u>

Step-by-step explanation:

Given:

Initial speed of debris is, $s=120\ ft/s$

The height 'h' of the debris above the ground is given as:

$h(t)=-16t^2+120t$

As per question, $h(t)=56\ ft$ . Therefore,

$56=-16t^2+120t$

Rewriting the above equation into a standard quadratic equation and solving for 't', we get:

$-16t^2+120t-56=0\\\textrm{Dividing by -8 throughout, we get}\\\frac{-16}{-8}t^2+\frac{120}{-8}t-\frac{56}{-8}=0\\2t^2-15t+7=0$

Using quadratic formula to solve for 't', we get:

$t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t=\frac{-(-15)\pm \sqrt{(-15)^2-4(2)(7)}}{2(2)}\\\\t=\frac{15\pm \sqrt{225-56}}{4}\\\\t=\frac{15\pm\sqrt{169}}{4}\\\\t=\frac{15\pm 13}{4}\\\\t=\frac{15-13}{4}\ or\ t=\frac{15+13}{4}\\\\t=\frac{2}{4}\ or\ t=\frac{28}{4}\\\\t=0.5\ s\ or\ t=7\ s$

Therefore, the debris will reach a height of 56 ft twice.

When time $t=0.5\ s$ during the upward journey, the debris is at height of 56 ft.

Again after reaching maximum height, the debris falls back and at $t=7\ s$ , the height is 56 ft.

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3 years ago