Please help me !??!!!

Estimate the solution of the equation x - 8.1=5.3 to the nearest whole number

lord [1]

2 or 3 I would say... hope that helps : )

3 0

3 years ago

Answer and round to the nearest tenth . <img src="https://tex.z-dn.net/?f=2.1%5Csqrt%7B1.488%7D" id="TexFormula1" title="2.1

Illusion [34]

It is a good idea to get familiar with the operation of your calculator. If you're going to use on-line resources to work problems like this, you can make use of any of several good on-line calculators. Google and Bing search boxes will do calculations for you while observing all the rules of the Order of Operations.

The result of this computation is a number that begins 2.56.... Since the hundredths digit is more than 4, the tenths digit is rounded to the next higher value, from 5 to 6.

Rounded to tenths, 2.1√1.488 = 2.6

7 0

3 years ago

In list T, consists of 30 positive decimals. None of which are integers. The sum of the 30 decimals is S. The estimated sum of t

Masteriza [31]

Answer: E - S = (-16 and 6)

Step-by-step explanation:1/3 of the 30 decimals in T have an even tenths digit, it follows that 1/3*(30)=10 decimals in T have an even tenths digit.

Hence: Te =list of 10 decimals

Se = sum of all 10 decimals in Te

Ee =estimated sum of all 10 decimals in Te after rounding up.

Remaining 20 decimals in T all have an odd tenths digits.

To =list of this 20 decimals

So = sum of all 20 decimals in To

Eo = estimated sum of 20 decimals in To

Hence,

E = Ee + Eo and S =Se +So, hence:

E-S, =(Ee+Eo) - (Se+So) =(Ee-Se) +(Eo-So)

Ee-Se >10 (0.1)=1

S=10(1.8)+20(1.9) =18+38=56

E=10(2)+20(1)=40

E-S =40-56=-16.

AlsoS=10(1.2)+20(1.1)=34

E=10(2)+20(1)=40

E-S=40-34=6

6 0

3 years ago

sweaters and hoodies are on sale for the same price at old navy. you buy 4 sweaters and 2 hoodies. you also buy a pair of jogger

VARVARA [1.3K]

do u have any answer choices ??

8 0

3 years ago

Read 2 more answers

If a coin is tossed three times, find probability of getting

Assoli18 [71]

${\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}$

‣ A coin is tossed three times.

${\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}$

‣ The probability of getting,

1) Exactly 3 tails

2) At most 2 heads

3) At least 2 tails

4) Exactly 2 heads

5) Exactly 3 heads

${\large{\textsf{\textbf{\underline{\underline{Using \: Formula :}}}}}}$

$\star \: \tt P(E)= {\underline{\boxed{\sf{\red{ \dfrac{ Favourable \: outcomes }{Total \: outcomes} }}}}}$

${\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}$

★ When three coins are tossed,

then the sample space = {HHH, HHT, THH, TTH, HTH, HTT, THT, TTT}

[here H denotes head and T denotes tail]

⇒Total number of outcomes $\tt [ \: n(s) \: ]$ = 8

1) Exactly 3 tails 

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

$\therefore \sf Probability_{(exactly \: 3 \: tails)} = \red{ \dfrac{1}{8}}$

2) At most 2 heads

[It means there can be two or one or no heads]

Here

• Favourable outcomes = {HHT, THH, HTH, TTH, HTT, THT, TTT} = 7

• Total outcomes = 8

$\therefore \sf Probability_{(at \: most \: 2 \: heads)} = \green{ \dfrac{7}{8}}$

3) At least 2 tails 

[It means there can be two or more tails]

Here

• Favourable outcomes = {TTH, TTT, HTT, THT} = 4

• Total outcomes = 8

$\longrightarrow \sf Probability_{(at \: least \: 2 \: tails)} = \dfrac{4}{8}$

$\therefore \sf Probability_{(at \: least \: 2 \: tails)} = \orange{\dfrac{1}{2}}$

4) Exactly 2 heads 

Here

• Favourable outcomes = {HTH, THH, HHT } = 3

• Total outcomes = 8

$\therefore \sf Probability_{(exactly \: 2 \: heads)} = \pink{ \dfrac{3}{8}}$

5) Exactly 3 heads

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

$\therefore \sf Probability_{(exactly \: 3 \: heads)} = \purple{ \dfrac{1}{8}}$

$\rule{280pt}{2pt}$

8 0

1 year ago