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1 year ago

Is the function in this table linear or nonlinear and why?

Mathematics

1 answer:

In-s [12.5K]1 year ago

8 0

The function in the table is nonlinear because they plugged the same number into the equation twice.

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Solve for x and explain

galben [10]

Since the two lines are parallel, the angle labeled 130 is congruent to the angle labeled x+ 136 so you can set them equal to each other

130 = x + 136
subtract 136 from both sides

x = -6

4 0

2 years ago

Read 2 more answers

Select the correct answer. What is the 13th term of this arithmetic sequence? 132, 135, 138, 141, … A. 168 B. 172 C. 176 D. 179

puteri [66]

Answer:

168

Step-by-step explanation:

132, 135, 138, 141, 144, 147, 150, 153, 156, 159, 162, 165, 168

5 0

3 years ago

What does congruent mean

Vikentia [17]

The definition of congruent is:

~In agreement or harmony.

Hope this helps!!!

7 0

3 years ago

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The area of Terry's room at the old house was 96 ft.2. The area of Terry's room at the new house is 108 ft.2

Finger [1]

Answer:

12.5%

Step-by-step explanation:

First we need to calculate the change in the area of Terry's room this is

108 ft2 - 96 ft2 = 12 ft2

Then we use a direct proportion in order to find the percentage

96 ft2 ----- 100%

12 ft2 ----- p?

Solvin for p we have that

$p=\frac{12\times 100}{96}$

p=12.5

3 0

2 years ago

Read 2 more answers

(1) [6pts] Let R be the relation {(0, 1), (1, 1), (1, 2), (2, 0), (2, 2), (3, 0)} defined on the set {0, 1, 2, 3}. Find the foll

goldenfox [79]

Answer:

Following are the solution to the given points:

Step-by-step explanation:

In point 1:

The Reflexive closure:

Relationship R reflexive closure becomes achieved with both the addition(a,a) to R Therefore, (a,a) is $(0,0),(1,1),(2,2) \ and \ (3,3)$

Thus, the reflexive closure: $R={(0,0),(0,1),(1,1),(1,2),(2,0),(2,2),(3,0), (3,3)}$

In point 2:

The Symmetric closure:

R relation symmetrically closes by adding(b,a) to R for each (a,b) of R Therefore, here (b,a) is: $(0,1),(0,2)\ and \ (0,3)$

Thus, the Symmetrical closure:

$R={(0,1),(0,2),(0,3)(1,0),(1,1)(1,2),(2,0),(2,2),(3,0), (3,3)}$

8 0

2 years ago