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3 years ago

1 + 1=? ;) im totally joking. whoever answers first gets brainliest answer.

Mathematics

2 answers:

Inessa [10]3 years ago

5 0

2 Is the answer so there you go

Bingel [31]3 years ago

5 0

__________________1+1=2____________________

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If OK = 2x, QR = 12, and RT = x + 3, what is the length of chord KM?

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3 years ago

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The next number in series 7,9,13,29 is:

Alex17521 [72]

Answer:

285

Step-by-step explanation:

9 = 7 + 2¹

13 = 9 + 2²

29 = 13 + 2⁴

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Answer:

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4 years ago

If f(x) = x^2-1 which of the following ordered pairs would be on the graph of f(x)

Alex Ar [27]

These following ordered pairs are on the graph:

(0,1)
(5, 24)
(-2,3)

-------------------------------

An ordered pair (x, f(x)) will be on the graph if replacing them into the equation, we get an equivalence.

-------------------------------

The equation is:

$f(x) = x^2 - 1$

-------------------------------

(0,1)

Here, we test $x = 0, f(x) = 1$

Replacing into the equation:

$1 = 0^2 - 1$

$1 = -1$

False, so not on the graph.

-------------------------------

(0,1)

Here, we test $x = 1, f(x) = 0$

Replacing into the equation:

$0 = 1^2 - 1$

$0 = 0$

True, so on the graph.

-------------------------------

(3,5)

Here, we test $x = 3, f(x) = 5$

Replacing into the equation:

$5 = 3^2 - 1$

$5 = 8$

False, so not on the graph.

-------------------------------

(5,24)

Here, we test $x = 5, f(x) = 24$

Replacing into the equation:

$24 = 5^2 - 1$

$24 = 24$

True, so on the graph.

-------------------------------

(-2,3)

Here, we test $x = -2, f(x) = 3$

Replacing into the equation:

$3 = (-2)^2 - 1$

$3 = 3$

True, so on the graph.

-------------------------------

(-4,-17)

Here, we test $x = -4, f(x) = -17$

Replacing into the equation:

$-17 = (-4)^2 - 1$

$-17 = 15$

False, so not on the graph.

A similar question is given at brainly.com/question/2102317

6 0

3 years ago