Which expression is equivalent to 5(4x+3)-2x?a 18x+15b 18x+3c 7x+8d 2x+8

tatiyna

Given the triangles ABC and PQR.
Angle A = Angle P
Angle B = Angle Q
Angle C = Angle R

Angle B = 3v+4
Angle Q = 8v-6
Let's find v

3v+4 = 8v-6
-5v = -10
v = 2

Angle B = 3v + 4
Angle B = 3(2) + 4
Angle B = 10.

The correct answer is letter C. 10

8 0

4 years ago

In inches, Micah is 5 inches shorter than twice the height of Jasmine, who is 32 inches tall. How tall is Micah in inches?

Monica [59]

Micah is 5 inches shorter than twice the height of Jasmine

Micah = 5 inches shorter than 2 x Jasmine

Micah = 2 x Jasmine - 5 <em>(jasmine is 32 inches tall. Replace jasmine with 32)
</em>
Micah = 2 x 32 - 5

Micah = 64 - 5

Micah = 59

Micah is 59 inches tall

5 0

3 years ago

Read 2 more answers

Evaluate the following expressions for x = -4

Vilka [71]

Answer:

-1/16

-1/4

1

-4

16

Step-by-step explanation:

Put x as -4 and solve.

-4^-2 = 1/-4^2 = -1/16

-4^-1 = 1/-4 = -1/4

-4^0 = 1

-4^1 = -4

-4^2 = 16

6 0

4 years ago

Find the area of the circle. Leave your answer in terms of π. radius is 14 in.

Ray Of Light [21]

The formula of the area of the circle:

π × radius^2

In this case, given that the radius is 14 inches:

π × 14^2

=196π square inches

Therefore the answer is 196π square inches.

Hope it helps!

5 0

3 years ago

. Lightning Strikes It has been said that the probability of being struck by lightning is about 1 in 750,000, but under what cir

mrs_skeptik [129]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

$P(U |D ) = 0.198$

b

$P(O\ n \ B) = 0.188$

c

$P(O | B) = 0.498$

Step-by-step explanation:

The total number of deaths is mathematically represented as

$T = 16 + 23 + \cdots + 16$

$T =623$

The total number of deaths in 1996 - 2000 is mathematically represented as

$T_a = 16 + 23+ \cdots + 30$

$T_a = 235$

The total number of deaths in 2001 - 2005 is mathematically represented as

$T_b = 17 + 16 + \cdots + 23$

$T_b = 206$

The total number of deaths in 2006 - 2010 is mathematically represented as

$T_c = 15 + 17 + \cdots + 16$

$T_d = 182$

Generally the the probability that it would occur under the tree given that the death was after 2000 is mathematically represented as

$P(U |D ) = \frac{P(A \ n\ U )}{P(A)}$

Here $P(A \ n\ U )$ represents the probability that it was after 2000 and it was under the tree and this is mathematically represented as

$P(A \ n\ U ) = \frac{Z}{ T}$

Here Z is the total number of death under the tree after 2000 and it is mathematically represented as

$Z = 35 + 42$

=> $Z = 77$

=> $P(A \ n\ U ) = \frac{77}{ 623}$

=>

Also

$P(A)$ is the probability of the death occurring after 2000 and this is mathematically represented as

$P(A) = \frac{T_b + T_c}{ T}$

=> $P(A) = \frac{ 206+ 182}{623}$

=>

So

$P(U |D ) = \frac{\frac{77}{ 623} }{ \frac{ 206+ 182}{623}}$

=> $P(U |D ) = 0.198$

Generally the probability that the death was from camping or being outside and was before 2001 is mathematically represented as

$P(O | B) = \frac{T_z}{ T}$

Here $T_z$ is the total number of death outside / camping before 2001 and the value is 117

So

$P(O \ n \ B) = \frac{117}{623}$

=> $P(O\ n \ B) = 0.188$

Generally the probability that the death was from camping or being outside given that it was before 2001 is mathematically represented as

$P(O | B) = \frac{ P( O \ n \ B)}{ P(B)}$

Here $P(B)$ is the probability that it was before 2001 , this is mathematically represented as

$P(B ) = \frac{T_a}{T}$

=> $P(B ) = \frac{235}{623}$

So

$P(O | B) = \frac{ \frac{117}{623}}{ \frac{235}{623}}$

=> $P(O | B) = 0.498$

5 0

3 years ago