Question

Consider the equation for the formation of water. 2h2 o2 right arrow. 2h2o what is the theoretical yield of h2o if 130 g of h2o is produced from 18 g of h2 and an excess of o2? 18 g 81 g 130 g 160 g

Answer 1

The theoretical yield is the reaction yield that measures the product of the reaction from the conversion of the limiting reagent. The theoretical yield is 160 gm.

What is mass?

Mass or the theoretical yield is the result of the multiplication of mole and the molar mass of the compound.

The reaction between hydrogen and oxygen is shown as,

$\rm 2H_{2} + O_{2} \rightarrow 2H_{2}O$

Moles of water is calculated as:

$\begin{aligned}\rm moles &= \rm \dfrac{mass}{molar\; mass}\\\\&= \dfrac{18}{2}\\\\&= 9\;\rm moles\end{aligned}$

The theoretical yield of water is calculated as:

$\begin{aligned}\rm \text{weight of water} &= \rm moles \times molar \; mass\\\\&= 9 \times 18\\\\&= 162 \;\rm gm\end{aligned}$

Therefore, option D. 160 gm is the theoretical yield of water.

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