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maxonik [38]
2 years ago
5

In the electric field

id="TexFormula1" title="{\vec{E}=3x\hat{i}-2y\hat{j}+5z\hat{k}}" alt="{\vec{E}=3x\hat{i}-2y\hat{j}+5z\hat{k}}" align="absmiddle" class="latex-formula">, find the potential difference between the points A(1,3,5) and B(3,2,7)​
Mathematics
1 answer:
Nezavi [6.7K]2 years ago
5 0

Let's recall <em>that</em>, the potential difference between <em>any</em> two points X(x,y,z) and Y(a,b,c) is given <em>by</em> ;

  • {\boxed{\bf{V_{Y}-V_{X}=\displaystyle \bf -\int_{X}^{Y}\overrightarrow{E}\cdot \overrightarrow{dr}}}}

So, here ;

{:\implies \quad \sf \overrightarrow{E}=3x\hat{i}-2y\hat{j}+5z\hat{k}}

So, now our <em>second</em> component of the Integrand will just <em>be</em> ;

{:\implies \quad \sf \overrightarrow{dr}=dx\hat{i}+dy\hat{j}+dz\hat{k}}

So, now the <em>whole integrand</em> will just be ;

{:\implies \quad \sf \overrightarrow{E}\cdot \overrightarrow{dr}=(3x\hat{i}-2y\hat{j}+5z\hat{k})(dx\hat{i}+dy\hat{j}+dz\hat{k})}

{:\implies \quad \sf \overrightarrow{E}\cdot \overrightarrow{dr}=3xdx-2ydy+5zdz}

Now, Let's move <em>to</em> the final answer ;

{:\implies \quad \displaystyle \sf V_{Y}-V_{X}=-\int_{X}^{Y}3xdx-2ydy+5zdz}

As,X is the <em>point</em> (1,3,5) and Y being (3,2,7) , so seperate the integral into three integrals with limits as <em>follows</em> respectively;

{:\implies \quad \displaystyle \sf V_{Y}-V_{X}=-\bigg(\int_{1}^{3}3xdx-\int_{3}^{2}ydy+\int_{5}^{7}zdz\bigg)}

{:\implies \quad \displaystyle \sf V_{Y}-V_{X}=-\bigg(3\int_{1}^{3}xdx-2\int_{3}^{2}ydy+5\int_{5}^{7}zdz\bigg)}

{:\implies \quad \displaystyle \sf V_{Y}-V_{X}=-\bigg\{3\bigg(\dfrac{x^2}{2}\bigg)\bigg|_{1}^{3}-2\bigg(\dfrac{y^2}{2}\bigg)\bigg|_{3}^{2}+5\bigg(\dfrac{z^2}{2}\bigg)\bigg|_{5}^{7}\bigg\}}

{:\implies \quad \displaystyle \sf V_{Y}-V_{X}=-\bigg\{2\bigg(\dfrac{9}{2}-\dfrac12\bigg)-2\bigg(\dfrac{4}{2}-\dfrac92\bigg)+5\bigg(\dfrac{49}{2}-\dfrac{25}{2}\bigg)\bigg\}}

{:\implies \quad \displaystyle \sf V_{Y}-V_{X}=-\{3(4)-(-5)+5(12)\}}

{:\implies \quad \displaystyle \sf V_{Y}-V_{X}=-\{12+5+60\}}

{:\implies \quad \displaystyle \boxed{\bf{V_{Y}-V_{X}=-77\:\: Volt}}}

<em>Hence, this is the required answer </em>

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