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bonufazy [111]
1 year ago
12

The stress on a wire that support a load depend on?​

Physics
1 answer:
kykrilka [37]1 year ago
3 0

Answer:

Breaking stress for a wire depends only on material.

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Does Radiation Affects this question? If it doesn't, is the answer C?​
kotegsom [21]
The answer will be C
5 0
3 years ago
Answer the question fast please​
AnnZ [28]

Answer:

1

Explanation:

d = m \div v  \\ m = 0.8 \: v = 80\% \: also \: 0.8 \\ d = 0.8 \div 0.8 \\ d = 1

6 0
3 years ago
a vector has an x-component of 19.5m and a y-component of 28.4m. Find the magnitude and direction of the vector
Delicious77 [7]

Answer:

magnitude=34.45 m

direction=55.52\°

Explanation:

Assuming the initial point P1 of this vector is at the origin:

P1=(X1,Y1)=(0,0)

And knowing the other point is P2=(X2,Y2)=(19.5,28.4)

We can find the magnitude and direction of this vector, taking into account a vector has a initial and a final point, with an x-component and a y-component.

For the magnitude we will use the formula to calculate the distance d between two points:

d=\sqrt{{(Y2-Y1)}^{2} +{(X2-X1)}^{2}} (1)

d=\sqrt{{(28.4 m - 0 m)}^{2} +{(19.5 m - 0m)}^{2}} (2)

d=\sqrt{1186.81 m^{2}} (3)

d=34.45 m (4) This is the magnitude of the vector

For the direction, which is the measure of the angle the vector makes with a horizontal line, we will use the following formula:

tan \theta=\frac{Y2-Y1}{X2-X1}  (5)

tan \theta=\frac{24.8 m - 0m}{19.5 m - 0m}  (6)

tan \theta=\frac{24.8}{19.5}  (7)

Finding \theta:

\theta= tan^{-1}(\frac{24.8}{19.5})  (8)

\theta= 55.52\°  (9) This is the direction of the vector

3 0
3 years ago
A continental polar air mass forms in ____
Sladkaya [172]
I believe it is A bit not completely sure
7 0
2 years ago
How much heat is released upon converting one mole of steam (18.0
Anika [276]

4.65 × 10⁴ Joules of heat is released upon converting one mole of steam to water.

\texttt{ }

<h3>Further explanation</h3>

Specific Heat Capacity is the amount of energy needed to raise temperature of 1 kg body for 1°C.

\large {\boxed{Q = m \times c \times \Delta t} }

<em>Q = Energy ( Joule )</em>

<em>m = Mass ( kg ) </em>

<em>c = Specific Heat Capacity ( J / kg°C ) </em>

<em>Δt = Change In Temperature ( °C )</em>

Let us now tackle the problem!

\texttt{ }

<u>Given:</u>

initial temperature of steam = t = 100.0°C

specific heat capacity of water = c = 4.186 J/gK

mass of steam = m = 18.0 gram

final temperature of water = t' = 25.0°C

specific latent heat of vaporization of water = Lv = 2268 J/g

<u>Asked:</u>

heat released = Q = ?

<u>Solution:</u>

\boxed {\large {\texttt{steam 100}^oC \overset{[Q_1]}{\rightarrow} \texttt{water 100}^oC \overset{[Q_2]}{\rightarrow} \texttt{water 25}^oC}}

Q = Q_1 + Q_2

Q = mL_v + mc\Delta t

Q = 18.0(2268) + 18.0(4.186)(100-25)

Q = 40824 + 5651.1

Q = 46475.1 \texttt{ Joules}

Q \approx 4.65 \times 10^4 \texttt{ Joules}

\texttt{ }

<h3>Learn more</h3>
  • Efficiency of Engine : brainly.com/question/5597682
  • Flow of Heat : brainly.com/question/3010079
  • Difference Between Temperature and Heat : brainly.com/question/3821712

\texttt{ }

<h3>Answer details </h3>

Grade: College

Subject: Physics

Chapter: Thermal Physics

\texttt{ }

Keywords: Heat , Temperature , Block , Aluminium , Ice , Cold , Water

4 0
3 years ago
Read 2 more answers
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