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Fiesta28 [93]
2 years ago
6

A teaspoonful of white dwarf material on earth would weigh

Physics
1 answer:
sashaice [31]2 years ago
4 0

Answer:

15 tons

Explanation:

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How has light been described? As a force and a wave only as a particle only as a force as a particle and a wave only as a wave
Len [333]

Light is only described in waves

5 0
3 years ago
A copper wire has a radius of 3.5 mm. When forces of a certain equal magnitude but opposite directions are applied to the ends o
denpristay [2]

Answer:

The tensile stress on the wire is 550 MPa.

Explanation:

Given;

Radius of copper wire, R = 3.5 mm

extension of the copper wire, e =  5.0×10⁻³ L

L is the original length of the copper wire,

Young's modulus for copper, Y =  11×10¹⁰Pa.

Young's modulus, Y is given as the ratio of tensile stress to tensile strain, measured in the same unit as Young's modulus.

Y =\frac{Tensile \ stress}{Tensile \ strain} \\\\Tensile \ stress = Y*Tensile \ strain\\\\But, Tensile \ strain = \frac{extension}{original \ Length} = \frac{5.0*10^{-3} L}{L} = 5.0*10^{-3}\\\\Tensile \ stress = 11*10^{10} *5.0*10^{-3} \ = 550*10^6 \ Pa

Therefore, the tensile stress on the wire is 550 MPa.

8 0
2 years ago
Train car A is at rest when it is hit by train car B. The two cars, which have the same mass, stick together and move off after
Natali [406]

Answer:C The final velocity is half of trained car B's initial velocity.

Explanation:

7 0
3 years ago
Read 2 more answers
A proton in a uniform electric field moves along a straight line with constant acceleration. Starting from rest it attains a vel
Sav [38]

a) The acceleration of the proton is 5.0\cdot 10^{13} m/s^2

b) The time required to reach the given velocity is 2\cdot 10^{-8}s

Explanation:

a)

This is a motion at constant acceleration, so we can use the following suvat equation:

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance covered

For the proton in this problem, we have:

v=1,000,000 m/s is the final velocity

u=0 is the initial velocity (it starts from rest)

s = 0.01 m is the distance covered

Solving for a, we find the acceleration:

a=\frac{v^2-u^2}{2s}=\frac{(1,000,000)^2-0}{2(0.01)}=5.0\cdot 10^{13} m/s^2

b)

For this part, we can use the following suvat equation instead:

v=u+at

where:

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time taken for the velocity to change from u to v

We have here the following data:

v=1,000,000 m/s is the final velocity

u=0 is the initial velocity (it starts from rest)

a=5.0\cdot 10^{13} m/s^2

Solving for t, we find

t=\frac{v-u}{a}=\frac{1,000,000}{5.0\cdot 10^{13}}=2\cdot 10^{-8}s

Learn more about accelerated motion here:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

5 0
3 years ago
The table below shows data of sprints of animals that traveled 75 meters. At each distance marker, the animals' times were recor
Sophie [7]

Answer:

i think its animal 4

Explanation:

7 0
3 years ago
Read 2 more answers
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