Question

the area of a rectangle is 99ft^2,and the L is 7ft more than twice the width. find the dimension of the rectangle.

Answer 1

A = L * W
A = 99
L = 2W + 7

99 = W(2W + 7)
99 = 2W^2 + 7W
-2W^2 - 7W + 99 = 0
(-2W + 11)(W + 9) = 0

-2W + 11 = 0
-2W = -11
W = -11/-2
W = 5.5

W + 9 = 0
W = -9 .....not this one because it is negative

so the width (W) = 5.5ft <====
L = 2W + 7 .....2(5.5) + 7 = 18 ft is the length (L) <==