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kolbaska11 [484]
2 years ago
5

An aircraft​ (at Z) is spotted by two observers​ (at X and​ Y) who are L=1750 feet apart . As the airplane passes over the line

joining​ them, each observer takes a sighting of the angle of elevation to the​ plane, as indicated in the figure. If If A=30 degrees and B=20 degrees how high is the​ airplane?
Mathematics
1 answer:
valentinak56 [21]2 years ago
6 0

Answer:

at aircraft(at z) sported by

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The class president is organizing a class trip to a nearby amusement park for 314 students. The regular price is $35 per ticket.
salantis [7]

Answer:

287 students were eligible for the discount :)

Step-by-step explanation:

7 0
3 years ago
It is a well-known fact that 50% of the general population are rascals (P(R) = 0.5) and 50% of the general population are not ra
aleksley [76]

Answer:

The answer is D. 0.75

Step-by-step explanation:

Let call R the event that a person is rascal, RC a person is not rascal, TH a person use top hat and NTH a person don’t use top hat.  

From the information on the question we have 4 options with their respective probability:

1. A person could be rascal and use top Hat: this probability is calculate as the multiplication of the probability of be a rascal (0.5) and use a top hat (0.9), then:

P(R y TH)=0.5*0.9=0.45

2. A person could be rascal and don’t use top Hat: this probability is calculate as the multiplication of the probability of be a rascal (0.5) and not use a top hat (0.9), then:

P(R y NTH)=0.5*0.1=0.05

3. A person could be not rascal and use top Hat: this probability is calculate as the multiplication of the probability of not be a rascal (0.5) and use a top hat (0.3), then:

P(RC y TH)=0.5*0.3=0.15

4. A person could be not rascal and not use top Hat: this probability is calculate as the multiplication of the probability of not be a rascal (0.5) and not use a top hat (0.7), then:

P(RC y NTH)=0.5*0.7=0.35

Then the probability that a person is a rascal given that he is wearing a top hat could be written and calculate as:

P(R/TH)=\frac{P(R y TH)}{P(TH)}

For calculate P(TH) we need to sum all the option in which TH is involve so:

P(TH) = P(R y TH)+ P(RC y TH)

P(TH)=0.45+0.15=0.6

Replacing values on the first equation we get:

P(R/TH)=\frac{0.45}{0.6} =0.75

So, the probability that a person is a rascal given that he is wearing a top hat is 0.75

5 0
3 years ago
Can somebody please help me? :(
Natasha2012 [34]

Answer:

143 square meters

Step-by-step explanation:

The surface has a width of 11 meters and a length of 13 meters.

13 x 11 = 143.

Is this correct?

5 0
2 years ago
Assume that lines that appear to be tangent are tangent. O is the center of the circle. Find the value of x.
MariettaO [177]
Draw an imaginary line from the vertex of angle x to the center of the circle.
This divides the 4-sided polygon into two right triangles.  For example, the upper right triangle has an acute angle whose measure is 135 degrees / 2, or 67.5 degrees, and the another acute angle whose measure is x/2.

x/2 and 67.5 degrees are complementary angles, so x/2 + 67.5 deg = 90 deg.  Thus, x/2 = 22.5 deg, and so x = 45 deg.  (answer)
8 0
3 years ago
A bucket that weighs 5 lb and a rope of negligible weight are used to draw water from a well that is 60 ft deep. The bucket is f
mestny [16]

Answer:

The value is W= 2640 \  ft \cdot lb

Step-by-step explanation:

From the question we are told that

The weight of the bucket is F =  5 lb

The depth of the well is x_1 =  60 \ ft

The weight of the water is W_w  =  42 lb

The rate at which the bucket with water is pulled is v  = 1.5 \  ft/s

The rate of the leak is r = 0.15 lb/s

Generally the workdone is mathematically represented as

W =  \int\limits^{x_1}_{x_o} {G(x)} \, dx]

Here G(x) is a function defining the weight of the system (water and bucket ) and it is mathematically represented as

G(x) =  F  +  (W_w- Ix)

Here I is the rate of water loss in lb/ft mathematically represented as

I  = \frac{r}{v}

=> I  = \frac{0.15 }{1.5 }

=> I  = 0.1

So

G(x) =  5  +  (42- 0.1x)

=> G(x) =  47- 0.1x)

So

W =  \int\limits^{60}_{0} {47- 0.1x} \, dx]

=> W =  [47x - \frac{0.1x^2}{2} ]|\left 60} \atop {0}} \right.

=> W= [47(60) - 0.05(60)^2]

=> W= 2640 \  ft \cdot lb

7 0
3 years ago
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