An aircraft (at Z) is spotted by two observers (at X and Y) who are L=1750 feet apart . As the airplane passes over the line
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answer
D 2
factor
factor the equation into (x + a) and (x + b) so that a + b = -2 and a * b = -8
the two numbers that meet these conditions are a = -4 and b = 2
find solutions
set both (x - 4) and (x + 2) equal to zero to find your solutions
x - 4 = 0
x = 4
x + 2 = 0
x = -2
add solutions
since the two solutions are x = 4 and x = -2, add them together to get your final answer
4 + (-2) = 2
Answer:
89.1° or -1.4°
Step-by-step explanation:
1. Location:
You are on the Mont-Saint-Jean escarpment, near the Belgian town of Waterloo.
The French troops are about 50 m below you and 1.2 km distant.
2. Finding the firing angle
Data:
R = 1200 m
u = 600 m/s
h = -50 m (the height of the target)
a = 9.8 m/s²
We have two conditions.
Horizontal distance
(1) 1200 = 600t cosθ
Vertical distance
(2) -50 = 600t sinθ - 4.9t²
Divide each side of (1) by 600cosθ.
Substitute (3) into (2)
Recall that
(5) sec²θ = 1/cos²θ = tan²θ + 1
Substitute (5) into (4)
Set up a quadratic equation
Solve for θ
Use the quadratic formula.
tanθ = 61.249 or -0.025
θ = arctan(61.249) = 89.1° or
θ = arctan(-0.025) = -1.4°