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serious [3.7K]
3 years ago
14

Need help immediately​

Mathematics
1 answer:
vekshin13 years ago
3 0
The answer is 6*square rooted*2
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HIGH SCHOOL MATH ....
umka21 [38]

Answer:

The value of B (base\ area) = 27m^2

Step-by-step explanation:

Let's recall the the formula for volume of a pyramid.

Volume of a Pyramid = \frac{1}{3}\times B\times H}....equation (1)

where B=Base\ area (m^2) and H=height\ (m)

Now we have been given the values of V and H and have to find the value of B

Plugging the values of V and H in equation (1)

B=\frac{3\times V}{H}= \frac{3 \times 81}{9} = 27\ m^2

Now we can also check our previous results.

V = \frac{24\times 7}{3}=8 \times 7 =56\ m^3

So, our final answer is 27\ m^2

7 0
3 years ago
Please help me with this
creativ13 [48]

Answer:

Step-by-step explanation:

(-3,-2)

7 0
2 years ago
The coefficient in the term 7xy is​
Lubov Fominskaja [6]

Answer:

The coefficient is 7

Step-by-step explanation:

The coefficient of an algebraic expression is the number that is being multiplied by a variable or multiple variables. In this case, 7 is being multiplied by x and y, so 7 is the coefficient.

5 0
2 years ago
Katrina wants to build a fence around her Square Garden the garden has an area of 121 square feet How much Fencing will Katrina
Sindrei [870]

Answer:

<em>The perimeter of the fencing is 44 feet (Option D)</em>

Step-by-step explanation:

<u>Area and Perimeter</u>

A square shape of side length (a) has an area given by:

A = a^2

And its perimeter is calculated as:

P = 4a

The area of Katrina's square garden is given as A=121 square feet. We need to calculate the side length by solving for a:

a=\sqrt{121}

a = 11 feet

Once we know the value of a, then we calculate the perimeter:

P = 4*11 = 44

The perimeter of the fencing is 44 feet (Option D)

7 0
2 years ago
Find the equation for the line that passes through the point (5,-3), and that is perpendicular to the line with the equation y-1
8090 [49]

Answer:

y+3=-4(x-5)

Explanation:

Part A

Given the line:

y-1=\frac{1}{4}(x-2)

We want to find the equation of a perpendicular line that passes through the point (5,-3),

First, determine the slope of the perpendicular line.

Comparing the given line with the slope-point form:

\begin{gathered} y-y_1=m(x-x_1) \\ \implies\text{Slope},m=\frac{1}{4} \end{gathered}

By definition, two lines are perpendicular if the product of their slopes is -1.

Let the slope of the perpendicular line = n

\begin{gathered} \implies\frac{1}{4}n=-1 \\ n=-4 \end{gathered}

Thus, using a slope of -4 and a point (5,-3), we find the equation of the line.

\begin{gathered} y-y_1=m(x-x_1) \\ y-(-3)=-4(x-5) \\ y+3=-4(x-5) \end{gathered}

The equation of the perpendicular line in the slope-point form is:

y+3=-4(x-5)

Part B

In order to graph the line, first, find two points on the line.

When x=0

\begin{gathered} y+3=-4(0-5) \\ y+3=20 \\ y=20-3=17 \\ \implies(0,17) \end{gathered}

When y=1

\begin{gathered} 1+3=-4(x-5) \\ 4=-4(x-5) \\ \frac{4}{-4}=x-5 \\ -1=x-5 \\ x=5-1=4 \\ \implies(4,1) \end{gathered}

Join the points (0,17) and (4,1) as shown in the graph below:

3 0
1 year ago
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