f(-a) is the remainder when f(x) is divided by (x+a). This can be obtained by remainder theorem for polynomials.
<h3>What is the required remainder?</h3>
Given that f(x) is divided by (x+a) and leaves a reminder
Using the remainder theorem for polynomials we get,
f(x) = (x+a)·g(x) + r, where g(x) is the quotient and r is the remainder.
Put x = -a, then
f(-a) = (-a+a)·g(-a) + r
f(-a) = (0)·g(x) + r
f(-a) = r
f(-a) is the remainder.
Hence f(-a) is the remainder when f(x) is divided by (x+a).
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Answer:
18c-30d+36
Step-by-step explanation:
Step-by-step explanation:
step 1. a diagram is important and can be uploaded. you will get a quicker answer with a diagram
step 2. triangle RST is a right triangle so we can use trigonometry to find <S
step 3. the adjacent side of <S is ST and the hypotenuse is RS so we will use cos
step 4. cosS = adj/hyp = ST/RS = 2.7/4.9
step 5. <S = 56.6° using inverse cos.
Answer: x=7
Step-by-step explanation: First you distribute the 12 to (10-x). That then gives you 15x+120-12x=141. Now you combine like terms. So you do 15x-12x=3x. Your new equation now is 3x+120=141. Subtract 120 from 141 and mark it out. That leaves you with 3x=21. Divide both sides by 3. Your final answer is x=7.