Answer:
(i)unique solution
Explanation:
We solve for x1 thus in the first equation:
x1-3x3=-3
x1-9=-3
x1=-3+9
x1= 6
We solve for a thus in the second equation:
2x1+ax2-x3=-2
2+a2-x3=-2
a2-x3=-4
a2=-4+x3
Answer:
115 in²
Step-by-step explanation:
SA = Area of triangular surfaces + area of the square base
SA= 2bh + b²
SA = 2(5)(9)+5²
SA = 90+25
SA = 115
You can perform the horizontal line test on the original to see if the inverse will be a function. You will not perform the horizontal line test on the inverse.
There is only one statement that is true: B. The graph of the function is a parabola.
<h3>How to study and interpret the characteristics of quadratic equations</h3>
In this question we have a <em>quadratic</em> equation, whose characteristics have to be inferred and analyzed. We need to prove each of the five choices presented in the statement:
Choice A:
If we know that x = - 10, then we evaluated it at the function:
f(- 10) = (- 10)² - 5 · (- 10) + 12
f(- 10) = 162
False
Choice B:
By analytical geometry we know that all functions of the form y = a · x² + b · x + c always represent parabolae.
True
Choice C:
The <em>quadratic</em> function opens up as its <em>leading</em> coefficient is greater that 0.
False
Choice D:
If we know that x = 20, then we evaluate it at the function:
f(20) = 20² - 5 · (20) + 12
f(20) = 312
False
Choice E:
If we know that x = 0, then we evaluate it at the function:
f(0) = 0² - 5 · (0) + 12
f(0) = 12
There is only one statement that is true: B. The graph of the function is a parabola.
To learn more on quadratic equations: brainly.com/question/1863222
#SPJ1
