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1 year ago

Solve the following pair of equations by elimination method: x+y=4, 2x+y=3

Mathematics

1 answer:

allsm [11]1 year ago

5 0

Answer:

x = 1

y = 5

Step-by-step explanation:

x + y = 4 __ (1)

2x + y = 3 __ (2)

equation (1) x 2, (2) x 1

2x + 2y = 8

2x + y = 3

0 + y = 5

y= 5 (ANS)

x + y = 4

x + 5 = 4

x = 5 - 4

x = 1 (ANS)

I HOPE MY ANSWER IS CORRECT IF NOT I APOLOGIZE.

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Given : A poker hand consisting of 9 cards is dealt from a standard deck of 52 cards.

The total number of cards in a deck 52

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$=\dfrac{\dfrac{12!}{6!6!}\times\dfrac{40!}{3!37!}}{\dfrac{52!}{9!\times43!}}\ \ [\because\ ^nC_r=\dfrac{n!}{r!(n-r)!}]\\\\=\dfrac{228}{91885}$

Hence, the probability that the hand contains exactly 6 face cards. is $\dfrac{228}{91885}$ .

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