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3 years ago

Which of the following lines is parallel to x = 4?

Mathematics

2 answers:

sladkih [1.3K]3 years ago

5 0

we know that

The line $x=4$ is parallel to the y-axis and is perpendicular to the x-axis

therefore

The line $x=2$ is parallel to the line $x=4$ , because is parallel to the y-axis and is perpendicular to the x-axis too

using a graphing tool

see the attached figure

the answer is

$x=2$

tatyana61 [14]3 years ago

3 0

It would be x=2 because the line x=4 would go on 4 on the x-axis and 2 would go on 2 on the
x-axis

It sounds confusing but look at picture

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What is the slope of a line perpendicular to the line containing the points (4,-7) and (-5,-1)? Express your answer as a common

just olya [345]

Answer:

3/2

Step-by-step explanation:

Slope 1 = (-1+7)/(-5-4) = 6/(-9) = -2/3

Slope 2 perpendicular to Slope 1 :

-1 ÷ -⅔ = 3/2

6 0

3 years ago

Help please and make sure the answer is right! Please :(

likoan [24]

You see how these 2 angles marked are both inside the 2 parallel lines?

And they are on opposite side of the transversal, the line crossing the 2 parallel lines?

These 2 angles are alternate interior angles and they are equal, I think you can do the last part by yourself.

8 0

3 years ago

I need help w/ this!! thank you

Fittoniya [83]

<h3>Answer:</h3>

$\boxed{\pink{\sf \leadsto Yes \ there \ is \ a \ solution \ of \ the \ given \ inequality .}}$

<h3>Step-by-step explanation:</h3>

A inequality is given to us and we need to convert it into standard form and see whether if it has a solution . So let's solve the inequality.

The inequality given to us is :-

$\bf\implies |2y + 3 | - 1 \leq 0 \\\\\bf\implies |2y+3|\leq 1 \\\\\bf\implies (|2y+3|)^2 \leq 1^2 \\\\\bf\implies (2y+3)^2 \leq 1 \\\\\bf\implies (2y)^2+3^2+2(2y)(3) \leq 1 \\\\\bf\implies 4y^2+9+12y - 1 \leq 0 \\\\\bf\implies 4y^2+12y+8 \leq 0 \\\\\bf\implies 4( y^2 + 3y + 2 ) \leq 0 \\\\\bf\implies y^2+3y +2 \leq 0 \:\:\bigg\lgroup \purple{\bf Standard \ form \ of \ inequality }\bigg\rgroup \\\\\bf\implies y^2y+2y+y+2 \leq 0 \\\\\bf\implies y(y+2)+1(y+2)\leq 0 \\\\\bf\implies ( y+2)(y+1)\leq 0 \\\\\bf\implies \boxed{\red{\bf y \leq (-2) , (-1) }}$

Let's plot a graph to see its interval . Graph attached in attachment .

Now we can see that the Interval notation of would be ,

$\boxed{\boxed{\orange \tt \purple{\leadsto}y \in [-2,-1] }}$

<h3>Hence the standard form of inequality is y²+3y +2 ≤ 0 and the Solution set of the inequality is [ -2 , -1 ] .</h3>

4 0

2 years ago

HELP PRETTY PLEASE THIS IS URGENT NEED IN THE NEXT HOUR!!

zmey [24]

Answer:

(- 2, 6 )

Step-by-step explanation:

Given the equations

3x + 2y = 6 → (1)

$\frac{2}{3}$ y - x = 6 ( multiply through by 3 to clear the fraction )

2y - 3x = 18 ( add 3x to both sides )

2y = 18 + 3x → (2)

Substitute 2y = 18 + 3x into (1)

3x + 18 + 3x = 6

6x + 18 = 6 ( subtract 18 from both sides )

6x = - 12 ( divide both sides by 6 )

x = - 2

Substitute x = - 2 into (1) and solve for y

3(- 2) + 2y = 6

- 6 + 2y = 6 ( add 6 to both sides )

2y = 12 ( divide both sides by 2 )

y = 6

solution is (- 2, 6 )

7 0

2 years ago

Marathon runner covered the whole distance in 4 hours running at a constant speed of 8.1 km per hour. How long would it take him

katen-ka-za [31]

Answer: it will take him 4.5 hours to cover same distance

Step-by-step explanation:

Marathon runner covered the whole distance in 4 hours running at a constant speed of 8.1 km per hour.

Speed = distance / time

Distance = speed×time

Therefore, distance covered by the marathon runner in in 4 hours, running at a speed of 8.1 km per hour is

8.1 × 4 = 32.4 kilometers

if he decreased the speed to 7.2 km per hour, the distance remains 32.4 kilometers. Therefore,

At 7.2 km per hour, the time it would take him to cover the same distance would be

Distance/ speed = 32.4/7.2 = 4.5 hours

8 0

3 years ago