Question

How many solutions are there for the quadratic equation? Y=x^2+12x+36 Show work

Answer 1

$\\ \rm\rightarrowtail x^2+12x+36=0$

$\\ \rm\rightarrowtail x^2+6x+6x+36=0$

$\\ \rm\rightarrowtail (x+6)(x+6)=0$

Only one solution present

x=-6

Answer 2

Answer:

1 solution

• x = -6

Explanation:

$\rightarrow \sf y=x^2+12x+36$

$\rightarrow \sf x^2+12x+36=0$

$\rightarrow \sf x^2+6x+6x+36=0$

$\rightarrow \sf x(x+6)+6(x+6)=0$

$\rightarrow \sf (x+6)(x+6)=0$

$\rightarrow \sf x=-6$

Hence there is only one solution for this quadratic equation and the value is -6