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AURORKA [14]
2 years ago
9

A bag contains 6 red marbles, 4 blue marbles, 7 green marbles, and 3 yellow marbles

SAT
1 answer:
krok68 [10]2 years ago
5 0

Answer:

20 marbles

Explanation:

6 red marbles

4 blue marbles

7 green marbles

3 yellow marbles

<h3>6+4+7+3=20</h3>

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The difference of the two solutions of x^2-17x+c=0 is 1.
Blizzard [7]

Answer:

c=17×-2

Explanation:

c+12

x= ------------------

17

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A fraction bar can be used as a grouping symbol
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Yes i think i can :DDDD

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“People should always obey the government or society will fall apart .”Do you agree ? Explain your answer
Semenov [28]
Yes it’s better to listen to the government because they have a higher power than you
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3 years ago
What is the best way to be successful in an examination which will be done before 1 month? ​
steposvetlana [31]

Answer:

According to my experience, revising the chapters before 1 month would really be beneficial. If you have the habit of following time table then you can make one and set the target to finish the syllabus right 3 or 4 days before examination which would make you feel confident. Find your distraction factor and try your best to avoid it. Practicing maths at night and reading the other subjects at morning will be more suitable. You can write the things on your rough copy which would really help you to memorize for language subject. And for maths you may start from the easy questions and you may go to difficult ones. That will help you somehow to develop interest. Dont choose a place like bed to study. Sit in such place where you won't feel sleepy. Dont feel pressurize while reading.

4 0
3 years ago
What maximum amount of ammonia in kilograms can be synthesized from 5.22 kg of h2 and 31.5 kg of n2?
Fiesta28 [93]

Consider the unbalanced reaction,

H₂ + N₂   ===>   NH₃

Balance it to get

3 H₂ + N₂   ===>   2 NH₃

This tells you that for every 3 moles of H₂ and 1 mole of N₂ among the reactants, 2 moles of NH₃ are produced.

Look up the molar masses of each component element:

• H : 1.008 g/mol     ===>   H₂ : 2.016 g/mol

• N : 14.007 g/mol     ===>   N₂ : 28.014 g/mol

• NH₃ : 17.031 g/mol

Convert the given mass to moles for each reactant:

• H₂ :

(5.22 kg) × (1000 g/kg) × (1/2.016 mol/g) ≈ 2589.29 mol

• N₂ :

(31.5 kg) × (1000 g/kg) × (1/28.014 mol/g) ≈ 1124.44 mol

Now,

(2589.29 mol H₂) : (1124.44 mol N₂) ≈ (2.30 mol H₂) : (1 mol N₂)

so that the amount of N₂ consumed is

(2589.29 mol H₂) × (1 mol N₂) / (3 mol H₂) ≈ 863.095 mol N₂

leaving an excess of about 261.343 mol N₂, and producing

(2589.29 mol H₂) × (2 mol NH₃) / (3 mol H₂) ≈ 1726.19 mol NH₃

Convert this to a mass :

(1726.19 mol) × (17.031 g/mol) × (1/1000 kg/g) ≈ 29.3987 kg

So, up to 29.4 kg of NH₃ can be synthesized.

4 0
3 years ago
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