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2 years ago

This is from gradpoint, please help me y’all :((

Mathematics

2 answers:

Zepler [3.9K]2 years ago

7 0

Answer:

No, these functions fail to be inverses of each other.

Step-by-step explanation:

We have two functions :

f(x) = 3x + 2
g(x) = $\frac{x-2}{3}$

Let's take the function f(x) and take x = 1.

f(1) = 3(1) + 2
f(1) = 5 [Keep this in mind]
If f(1) is 5, then if g(x) is an inverse function, g(1) should be $\frac{1}{5}$

Let's try the same with g(x).

g(1) = $\frac{1-2}{3}$
g(1) = $-\frac{1}{3}$

Clearly, they are not inverse functions of each other.

Afina-wow [57]2 years ago

5 0

Answer if im not misstaken its no

Step-by-step explanation:

because ur working with fractions they dont = the same thing. lmk if im wrong

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(b) Amrita is 8 years

egoroff_w [7]

Answer:

cheap.....

7/10 + 3/10

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5 0

3 years ago

. A biologist is comparing the growth of a population of flies per week to the number of flies an iguana will consume per week.

Veseljchak [2.6K]

We are given the equation 3^x = 2x + 1 in which x as the number of days of the population of flies and the number of flies consumed by iguana each week. In this case, the other equation described when x =7 population is not more than 8. The graph is a logarithmic graph

3 0

3 years ago

Read 2 more answers

Please give an explanation as well as an answer :)

STatiana [176]

Answer: It is 10 because there are 2 other faces and 8+2=10

Step-by-step explanation:

3 0

3 years ago

Solve the following equation by factoring:9x^2-3x-2=0

olya-2409 [2.1K]

Answer:

The two roots of the quadratic equation are

$x_1= - \frac{1}{3} \text{ and } x_2= \frac{2}{3}$

Step-by-step explanation:

Original quadratic equation is $9x^{2}-3x-2=0$

Divide both sides by 9:

$x^{2} - \frac{x}{3} - \frac{2}{9}=0$

Add $\frac{2}{9}$ to both sides to get rid of the constant on the LHS

$x^{2} - \frac{x}{3} - \frac{2}{9}+\frac{2}{9}=\frac{2}{9}$ ==> $x^{2} - \frac{x}{3}=\frac{2}{9}$

Add $\frac{1}{36}$ to both sides

$x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{2}{9} +\frac{1}{36}$

This simplifies to

$x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{1}{4}$

Noting that (a + b)² = a² + 2ab + b²

If we set a = x and b = $\frac{1}{6}\right)$ we can see that

$\left(x - \frac{1}{6}\right)^2$ = $x^2 - 2.x. (-\frac{1}{6}) + \frac{1}{36} = x^{2} - \frac{x}{3}+\frac{1}{36}$

$\left(x - \frac{1}{6}\right)^2=\frac{1}{4}$

Taking square roots on both sides

$\left(x - \frac{1}{6}\right)^2= \pm\frac{1}{4}$

So the two roots or solutions of the equation are

$x - \frac{1}{6}=-\sqrt{\frac{1}{4}}$ and $x - \frac{1}{6}=\sqrt{\frac{1}{4}}$

$\sqrt{\frac{1}{4}} = \frac{1}{2}$

So the two roots are

$x_1=\frac{1}{6} - \frac{1}{2} = -\frac{1}{3}$

and

$x_2=\frac{1}{6} + \frac{1}{2} = \frac{2}{3}$

7 0

1 year ago

The following data are the distances between a sample of 20 retail stores and a large distribution center. The distances are in

sesenic [268]

Answer:

Variance = 1,227.27

Standard deviation = 35.03

Step-by-step explanation:

To calculate these, we use the following formulas:

Mean = (sum of the values) / n

Variance = ((Σ(x - mean)^2) / (n - 1)

Standard deviation = Variance^0.5

Where;

n = number of values = 20

x = each value

Therefore, we have:

Sum of the values = 29 + 32 + 36 + 40 + 58 + 67 + 68 + 69 + 76 + 86 + 87 + 95 + 96 + 96 + 99 + 106 + 112 + 127 + 145 + 150 = 1,674

Mean = 1,674 / 20 = 83.70

Variance = ((29-83.70)^2 + (32-83.70)^2 + (36-83.70)^2 + (40-83.70)^2 + (58-83.70)^2 + (67-83.70)^2 + (68-83.70)^2 + (69-83.70)^2 + (76-83.70)^2 + (86-83.70)^2 + (87-83.70)^2 + (95-83.70)^2 + (96-83.70)^2 + (96-83.70)^2 + (99-83.70)^2 + (106-83.70)^2 + (112-83.70)^2 + (127-83.70)^2 + (145-83.70)^2 + (150-83.70)^2) / (20 - 1) = 23,318.20 / 19 = 1,227.27

Standard deviation = 1,227.27^0.5 = 35.03

5 0

2 years ago