Find the slope of the line

In the equation y = 10 = 2x, what is the value of y when x = 3?

lutik1710 [3]

Answer:

10

Step-by-step explanation:

y = 10 - 2x

7 0

2 years ago

Read 2 more answers

Which products result in a difference of squares or a perfect square trinomial? check all that apply. (5x 3)(5x – 3) (7x 4)(7x 4

Scilla [17]

(7x + 4)(7x + 4) and (x – 9)(x – 9) are Perfect square trinomial. (5x + 3)(5x – 3) and (–3x – 6)(–3x + 6) shows the Difference of squares.

<h3>What is a perfect square?</h3>

A perfect square is a number system that can be expressed as the

square of a given number from the same system.

The following are the answers

(5x + 3)(5x – 3) Difference of squares

(7x + 4)(7x + 4) is a Perfect square trinomial

(2x + 1)(x + 2) has Neither a difference of squares nor a perfect square trinomial.

(4x – 6)(x + 8) has Neither a difference of squares nor a perfect square trinomial.

(x – 9)(x – 9) is Perfect square trinomial

(–3x – 6)(–3x + 6) = $(-3x)^2- ( -6)^2$ Difference of squares.

Learn more about perfect square:

brainly.com/question/1415730

8 0

2 years ago

Can you use the SAS Postulate, the AAS Theorem, or both to prove the triangles congruent?

nadezda [96]

AAS because there’s a vertical angle

3 0

3 years ago

Finish the following statement: In the altitude to hypotenuse theorem, the ALTITUDE is the geometric mean...

madam [21]

The hypotenuse is believe is what your looking for if not I do not understand because of how it’s worded

8 0

3 years ago

Someone plz help me with this asap!!!!!

Bas_tet [7]

Answer:

1.) $x=8\sqrt{3};y=16$

2.) $x=1;y=\frac{\sqrt{3}}{2}$

3.) $x=28 ; y=14\sqrt{3}$

4.) $x=24 ; y=12\sqrt{3}$

5.) $x=4\sqrt{3};y=8\sqrt{3}$

6.) $x=\frac{8\sqrt{3}}{3};y=\frac{16\sqrt{3}}{3}$

Step-by-step explanation:

Use the 30°-60°-90° formulas:

a. $longer$ $leg=\sqrt{3}*shorter$ $leg$

b. $hypotenuse=2*shorter$ $leg$

1.) Insert values for a:

$x=\sqrt{3}*8$

Simplify:

$x=8\sqrt{3}$

Insert values for b:

$y=2*8$

Simplify:

$y=16$

2.) Insert values for a:

$y=\sqrt{3}*\frac{1}{2}$

Simplify:

$y=\frac{\sqrt{3}}{2}$

Insert values for b:

$x=2*\frac{1}{2}$

Simplify:

$x=1$

3.) Insert values for a:

$y=\sqrt{3}*14$

Simplify:

$y=14\sqrt{3}$

Insert values for b:

$x=2*14$

Simplify:

$x=28$

4.)Insert values for a:

$y=\sqrt{3}*12$

Simplify:

$y=12\sqrt{3}$

Insert values for b:

$x=2*12$

Simplify:

$x=24$

5.) Insert values for a:

$12=\sqrt{3}*x$

Divide both sides by $\sqrt{3}$ and rationalize:

$\frac{12}{\sqrt{3}}=\frac{\sqrt{3}*x}{\sqrt{3}}\\\\\frac{12}{\sqrt{3}}=x\\\\\frac{\sqrt{3}}{\sqrt{3}}*\frac{12}{\sqrt{3}}\\\\\frac{12\sqrt{3}}{\sqrt{9}}\\\\\frac{12\sqrt{3}}{3}\\\\4\sqrt{3}=x$

Flip:

$x=4\sqrt{3}$

Insert values for b:

$y=2*4\sqrt{3}$

Simplify:

$y=8\sqrt{3}$

6.) Insert values for a:

$8=\sqrt{3}*x$

Divide both sides by $\sqrt{3}$ and rationalize:

$\frac{8}{\sqrt{3}}=\frac{\sqrt{3}*x}{\sqrt{3}}\\\\\frac{8}{\sqrt{3}}=x\\\\\frac{\sqrt{3}}{\sqrt{3}}*\frac{8}{\sqrt{3}}\\\\\frac{8\sqrt{3}}{\sqrt{9}}\\\\\frac{8\sqrt{3}}{3}=x$

Flip:

$x=\frac{8\sqrt{3}}{3}$

Insert values for b:

$y=2*\frac{8\sqrt{3}}{3}$

Simplify:

$y=\frac{16\sqrt{3}}{3}$

Finito.

5 0

3 years ago