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1 year ago

The number 2 is a factor of _________.

Mathematics

2 answers:

MissTica1 year ago

8 0

<h3>hello!</h3>

2 is a factor of all even numbers (numbers that end with 2, 4, 6, 8, 0)

Option A) is wrong because 1, 3, 5, 7, 9 & numbers that end with the digits listed above are not evenly divisible by 2; this is the reason why Option C) is wrong.

In order for a digit/number to be a factor of a number, it should be evenly divisible by that number.

Hope everything is clear; if you need any more explanation/clarification, kindly let me know, and I will comment and/or edit my answer. :)

zmey [24]1 year ago

5 0

the number 2 is a factor of all even numbers (b)

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Players on a softball team are randomly given a uniform with a two-digit number on the back. The numbers range from 10 to 99. Wh

Minchanka [31]

Answer:

1/10 or 10%

Step-by-step explanation:

99 possible numbers starting from 10

1,2,3,4,5,6,7,8,9 does not count

99-9=90

90 numbers total

possible numbers with a 0: 9

9/90 = 1/10 = 10%

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3 years ago

The table shows value for the function f, while the graph shows function g.

Sauron [17]

Answer:

Step-by-step explanation:

A is the right answer

f has the greater slope, 3. The slope of g is 2.

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3 years ago

The Students' Conjectures Emily and Zach have two different polynomials to multiply: Polynomial product A: (4x2 – 4x)(x2 – 4) Po

noname [10]

Complete Question:

Emily and Zach have two different polynomials to multiply: Polynomial product A: (4x2 – 4x)(x2 – 4) Polynomial product B: (x2 + x – 2)(4x2 – 8x) They are trying to determine if the products of the two polynomials are the same. But they disagree about how to solve this problem.

Answer:

$A = B$

Step-by-step explanation:

<em>See comment for complete question</em>

Given

$A: (4x^2 - 4x)(x^2 - 4)$

$B: (x^2 + x - 2)(4x^2 - 8x)$

Required

Determine how they can show if the products are the same or not

To do this, we simply factorize each polynomial

For, Polynomial A: We have:

$A: (4x^2 - 4x)(x^2 - 4)$

Factor out 4x

$A: 4x(x - 1)(x^2 - 4)$

Apply difference of two squares on x^2 - 4

$A: 4x(x - 1)(x - 2)(x+2)$

For, Polynomial B: We have:

$B: (x^2 + x - 2)(4x^2 - 8x)$

Expand x^2 + x - 2

$B:(x^2 + 2x - x - 2)(4x^2- 8x)$

Factorize:

$B:(x(x + 2) -1(x + 2))(4x^2- 8x)$

Factor out x + 2

$B:(x -1) (x + 2)(4x^2- 8x)$

Factor out 4x

$B:(x -1) (x + 2)4x(x- 2)$

Rearrange

$B: 4x(x - 1)(x - 2)(x+2)$

The simplified expressions are:

$A: 4x(x - 1)(x - 2)(x+2)$ and

$B: 4x(x - 1)(x - 2)(x+2)$

Hence, both polynomials are equal

$A = B$

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solniwko [45]

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3 years ago

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vekshin1

Answer:

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Step-by-step explanation:

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2 years ago

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