Answer:The based on this information interaction between these two species can best be described as COMPETITION. Correct option is B
Explanation:
Competition occurs between two species that shares the same requirements ( especially food) for survival.
Both the Western Toad and the Bull Frog has a similar niche because they require the same type of food (beetles, bees, and small aquatic insects) to survive in the environment of Arroyo Seco. Only one of the species will coexist in that environment and it's usually the survival of the fittest.
This explains the competitive exclusion principle proposed by Georgii Gause in 1934.
Answer:
Producers which means plants have the most energy in a food chain or web besides the sun and they give an organism more energy than a primary consumer or secondary consumer would. Plants absorb about 1% of the sunlight that strikes them. The rest is reflected into space or transmitted through objects.
Answer:
Water
Explanation:
Molecular oxygen is the terminal electron acceptor and serves to receive electrons from reduced NADH and FADH2 to reoxidize them. NADH and FADH2 are formed during glycolysis and Kreb's cycle. These reducing powers should be re-oxidized to enter in the first two steps of aerobic respiration again.
For the purpose, NADH, and FADH2 transfer their electrons to the molecular oxygen via electron transport chain. After accepting the electrons, molecular oxygen is oxidized into the water molecule. Therefore, radioactive oxygen isotope would appear in the form of a water molecule after completion of cellular respiration.
The level of organization that is the highest is: Organism, Organ System, Organ, and Tissue.
C would be you're answer, it is the "highest" out of all of them.
Answer:
(a) Frequency of M = 0.64
Frequency of N = 0.04
Frequency of MN= 0.32
(b) Expected frequencies of M = 0.648
Expected frequencies of MN = 0.304
Expected frequencies of N = 0.048
Explanation:
(a) If random mating takes place in the population, then the expected frequencies are
f(L(M)) = p = 0.8
F(L(N)) = q
q= 1 - p
= 1 - 0.8
= 0.2
Frequency of M = p^2 = ( 0.8)^2 = 0.64
Frequency of N = q^2 = (1-p)^2 = (1 - 0.8)^2 = (0.2)^2 = 0.04
Frequency of MN = 2pq = 2 * 0.8 * 0.2 = 0.32
(b)
F = inbreeding coefficient = 0.05
f(L(M)L(M)) = p^2 + Fpq = (0.8)^2 + 0.05 * 0.8 * 0.2 = 0.648
f(L(M)L(N)) = 2 pq - 2Fpq = 2 * 0.8 * 0.2 - ( 2 * 0.05 * 0.8 * 0.2) = 0.304
f(L(N)L(N)) = q^2 + Fpq = (0.2)^2 + ( 0.05 * 0.8 * 0.2) = 0.048
