Answer:
y = x^2 + 3x - 10
Step-by-step explanation:
x*x + 5*x + -2*x + 5*-2
= x^2 + 3x + -10
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(b). → Simplify: [{5^(x-+1) + 5^x}/{6×5^x}]
= [{5^(x+1+x)}/{6×5^x}]
= [{5^(2x+1)}/{6×5^x}]
= [{5^(2x+1)}/{6×5^x}]
= [{5^(2x+1-x)}/6]
= [{5^(x+1)}/6]Ans.
(c). 4a³b²
= 4(3)³(-2)²
Since, a = 3 and b = -2.
so,
= 4(3*3*3)(-2*-2)
= 4(27)(4)
= 108(4)
= 432Ans.
<u>also</u><u> </u><u>read</u><u> similar</u><u> questions</u><u>:</u> simplify 6/x-6+3x/x+5-1/(x-6)(x+5)..
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simplify the equation simplify x^5/8/x^1/6..
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Answer:
the integral result is I = 1/6
Step-by-step explanation:
For the region with vertices (0,0), (1,0), and (0,1) we have the
boundaries y=1-x , x=0 and y=0 for the integral then
1) integrating over the region y=1-x and y=0 for y , and then from x=1 to x=0
I = ∫∫ f (x,y) dx*dy = ∫₀¹∫₀¹⁻ˣ (x^2 + y^2 ) dy*dx = ∫₀¹ [(1-x)*x^2 + (1/3)(1-x)^3 - 0*x^2 + (1/3)0^3 ] dx = ∫₀¹ [x^2 - (2/3)x^3] dx = [(1/3)x^3 - (1/6) x^4 ]|₀¹= [(1/3)1^3 - (1/6) 1^4 ] - [(1/3)0^3 - (1/6) 0^4 ] = (1/3) - (1/6) = 1/6
2) integrating over the region x=1-y and x=0 for x , and then from y=1 to y=0 (the same process but changing y for x)
She is losing $20, so it indicates a negative number when really it is positive
The answer is "I" or "I and II".