All categories

2 years ago

Write the part-to-whole relationship for the fraction given below.

Mathematics

1 answer:

vivado [14]2 years ago

4 0

Answer:

1. Two ribbons, A and B. One third of A is equal to all of B. Draw a tape diagram to show the ribbons.

2. Half Robert’s piece of wire is equal to 2/3 of Maria’s wire. The total length of their wires is 10 feet. How much longer is Robert's wire than Maria's?

3. Half Sarah’s wire is equal to 2/5 of Daniel’s. Chris has 3 times as much as Sarah. In all, their wire measures 6 ft. How long is Sarah’s wire in feet?

You might be interested in

Im getting my grade up soo help

Ket [755]

Where is pic…………………,,,,,

4 0

1 year ago

Read 2 more answers

Write each expression with a single rational exponent. Show each step of your process. Which expressions are equivalent? Justify

Lena [83]

The expression of all the algebra as single rational exponent are; As written below.

<h3>How to Express Exponents?</h3>

1) We want to express ⁴√x³. This can be expressed as;

x^(3/4)

2) We want to express the exponent ¹/x⁻¹. This is expressed as a single rational exponent as; x

3) We want to have the given expression as a single rational exponent. The expression is; ¹⁰√(x⁵ · x⁴ · x²)

We add the exponents to get;

¹⁰√(x¹¹) = x^(¹¹/₁₀)

4) x^(¹/₃) * x^(¹/₃) * x^(¹/₃)

We just add the exponents to get;

x¹ = x

Read more about Exponents at; brainly.com/question/11761858

#SPJ1

3 0

1 year ago

PLEASE PLEASE PLEASE HELP ASAP *grade 9 work* best answer gets brainliest :)

skelet666 [1.2K]

For number 13 x=70 and y=115 hope this helped

7 0

2 years ago

Read 2 more answers

Sam studied guinea pigs for his science fair project. He found that the amount of weight the guinea pigs gained varied directly

Oliga [24]

From the given above, we can formulate the equation:

W = C / 218

By substituting the given values:

W = 1090 calories / (218 calories / 1 ounce)

W = 5 ounce

<span>Therefore the guinea pigs will gain additional 5 ounce if the diet was increased by 1090 calories.</span>

4 0

2 years ago

<img src="https://tex.z-dn.net/?f=%24a%2Ba%20r%2Ba%20r%5E%7B2%7D%2B%5Cldots%20%5Cinfty%3D15%24%24a%5E%7B2%7D%2B%28a%20r%29%5E%7B

riadik2000 [5.3K]

Let

$S_n = \displaystyle \sum_{k=0}^n r^k = 1 + r + r^2 + \cdots + r^n$

where we assume |r| < 1. Multiplying on both sides by r gives

$r S_n = \displaystyle \sum_{k=0}^n r^{k+1} = r + r^2 + r^3 + \cdots + r^{n+1}$

and subtracting this from $S_n$ gives

$(1 - r) S_n = 1 - r^{n+1} \implies S_n = \dfrac{1 - r^{n+1}}{1 - r}$

As n → ∞, the exponential term will converge to 0, and the partial sums $S_n$ will converge to

$\displaystyle \lim_{n\to\infty} S_n = \dfrac1{1-r}$

Now, we're given

$a + ar + ar^2 + \cdots = 15 \implies 1 + r + r^2 + \cdots = \dfrac{15}a$

$a^2 + a^2r^2 + a^2r^4 + \cdots = 150 \implies 1 + r^2 + r^4 + \cdots = \dfrac{150}{a^2}$

We must have |r| < 1 since both sums converge, so

$\dfrac{15}a = \dfrac1{1-r}$

$\dfrac{150}{a^2} = \dfrac1{1-r^2}$

Solving for r by substitution, we have

$\dfrac{15}a = \dfrac1{1-r} \implies a = 15(1-r)$

$\dfrac{150}{225(1-r)^2} = \dfrac1{1-r^2}$

Recalling the difference of squares identity, we have

$\dfrac2{3(1-r)^2} = \dfrac1{(1-r)(1+r)}$

We've already confirmed r ≠ 1, so we can simplify this to

$\dfrac2{3(1-r)} = \dfrac1{1+r} \implies \dfrac{1-r}{1+r} = \dfrac23 \implies r = \dfrac15$

It follows that

$\dfrac a{1-r} = \dfrac a{1-\frac15} = 15 \implies a = 12$

and so the sum we want is

$ar^3 + ar^4 + ar^6 + \cdots = 15 - a - ar - ar^2 = \boxed{\dfrac3{25}}$

which doesn't appear to be either of the given answer choices. Are you sure there isn't a typo somewhere?

7 0

1 year ago

Write the​ part-to-whole relationship for the fraction given below.

Write the part-to-whole relationship for the fraction given below.