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34kurt
2 years ago
6

Can somebody help me with this please and thanks

Mathematics
2 answers:
bearhunter [10]2 years ago
8 0

Answer:

120 1/3 cubes

Step-by-step explanation:

you have 5 thirds so 5 and 4 thirds so 4 and 2 wholes which is 6 thirds so you would multilpy them and the equation would be 5x4x6 and that equals 120.

Nadya [2.5K]2 years ago
7 0

Answer:

120 cubes are required.........

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for a field trip 4 students rode in cars and the rest filled nine buses. how many students were in each bus if 472 students were
Lemur [1.5K]
The answer is 52

x - the number of students in a bus

4 + 9x = 472
9x = 472 - 4
9x = 468
x = 468 / 9
x = 52
4 0
3 years ago
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A PE teacher is charting the weight and BMI of her students. The table below shows the measured weight for all of her students f
svetlana [45]

Answer:

122.67 average

Step-by-step explanation:

Mean = (every value added up)/(# of values)

Mean = (105 + 2(110) + 2(112) + 3(113) + 2(115) + 5(116) + 4(117) + 7(118) + 5(120) + 5(121) + 4(125) + 5(126) + 2(128) + 130 + 3(132) + 134 + 3(135) + 2(140) + 2(141) + 150)/60

= 7360/60

= 122.67

I had trouble understanding the data but I hope I did this right!

6 0
3 years ago
Write an equation that has a graph with the shape of y = x^2, but shifted left 3 units.
svetoff [14.1K]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}\\\\
--------------------\\\\

\bf % template detailing
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\

\bf \bullet \textit{ vertical shift by }{{  D}}\\
\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\
\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

now, with that template in mind, let's see

\bf y=x^2\implies 
\begin{array}{llll}
y=(&1x&-0)^2\\
&B&C
\end{array}

so, just change C to +3, thus C/B is 3/1
6 0
3 years ago
PLEASE HELP.
Harrizon [31]

ANSWER

The maximum y-value is 0.

EXPLANATION

The domain of the given absolute value function is (-∞, ∞) .

This means the function is defined for all real values of x.

The range of the function is (-∞, 0].

This can be rewritten as

y \leqslant 0

This means that, the highest y-value on the gray of this absolute value function is 0.

Hence the maximum y-value of the function is 0.

3 0
3 years ago
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Gekata [30.6K]

Answer: 8

Step-by-step explanation:

Umm idk

4 0
3 years ago
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