Let n be the smaller integer.
Step 2. Let n+1 be the larger and next consecutive integer.
Step 3. Let 3n be three times the smaller integer.
Step 4. Let 4(n+1) be four times the larger integer.
Step 5. Then 3n+4(n+1)=39 since three times the smaller of two consecutive integers is added to four times the larger will result in 39.
Step 6. Solving the equation in Step yields the following steps:
stWith n=5, then n+1=6 and check the sum 3*5+4*6=15+24=39...which is a true statement.
Step 7. ANSWER: The integers are 5 and 6
I hope the above steps were helpful.heyaaa
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hopefully it helps
The dimensions are 6x7 ////////////////////
Answer:
56
Step-by-step explanation:
If there can be only one 1 and only one 2, the remaining digits must all be 0. The digits 1 and 2 can be anywhere in the 8 digits, and can be in either order.
There are 8 possible locations in the sequence for the 1, then 7 possible locations for the 2. The total number of possibilities is 8·7 = 56.
12000000, 21000000, 10200000, 20100000, ..., 00000012, 00000021.
Answer:
25 or more
Step-by-step explanation:
30/1.is 24 so it would be 25 or more times for it to be a better deal
