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Lynna [10]
2 years ago
13

HELP ASAP PLEASE

Mathematics
1 answer:
Liula [17]2 years ago
3 0

distance : 15 units

coordinates :  (7,0) and (-8, 45)

slope:

\sf \rightarrow  \dfrac{y_2-y_1}{x_2-x_1}

\sf \rightarrow  \dfrac{45-0}{-8-7}

\sf \rightarrow  -3

equation:

\hookrightarrow \sf y - 0 = -3(x-7)

\hookrightarrow \sf y = -3x+21

the y-intercept of this function:

\hookrightarrow \sf y = -3(0)+21

\hookrightarrow \sf y =21

distance between both y-intercept :

  • 21 - 6
  • 15
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C = 9/28 = 0.321

https://www.tiger-algebra.com/drill/3c-3/4=2c/3/

3 0
3 years ago
Find the 13th term of the arithmetic sequence -3x+7, -5x+3, -7x-1, ...
oksano4ka [1.4K]

Answer:

a₁₃ = - 27x - 41

Step-by-step explanation:

The nth term of an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = - 3x + 7

d = a₂ - a₁ = - 5x + 3 - (- 3x + 7)

                 = - 5x + 3 + 3x - 7

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Then

a₁₃ = - 3x + 7 + 12(- 2x - 4)

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3 0
3 years ago
The general solution of 2 y ln(x)y' = (y^2 + 4)/x is
Sav [38]

Replace y' with \dfrac{\mathrm dy}{\mathrm dx} to see that this ODE is separable:

2y\ln x\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y^2+4}x\implies\dfrac{2y}{y^2+4}\,\mathrm dy=\dfrac{\mathrm dx}{x\ln x}

Integrate both sides; on the left, set u=y^2+4 so that \mathrm du=2y\,\mathrm dy; on the right, set v=\ln x so that \mathrm dv=\dfrac{\mathrm dx}x. Then

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\implies\ln|u|=\ln|v|+C

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\implies y^2=C|\ln x|-4

\implies y=\pm\sqrt{C|\ln x|-4}

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2 years ago
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a_sh-v [17]
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3x - 4 = 8
3x = 8 + 4
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x = 12/3
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3 years ago
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Zigmanuir [339]

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