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Nataly [62]
3 years ago
6

X+y=4 X-3y=12 Graph?

Mathematics
1 answer:
AlekseyPX3 years ago
8 0
I'll solve it algebraically


x+y=4
x-3y=12

multiply first equatoin by -1 and add to second

-x-y=-4
<u>x-3y=12 +</u>
0x-4y=8


-4y=8
divide both sides by -4
y=-2

sub back

x+y=4
x+-2=4
add 2 to both sides
x=6

x=6
y=-2
(6,-2)
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Lyrx [107]

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Step-by-step explanation:

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6 0
3 years ago
What is 15% of 60? How did you find your answer?​
Norma-Jean [14]

Answer:

15% of 60 is 9

Step-by-step explanation:

15%= 3/20

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180/20= 9

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5 0
3 years ago
Read 2 more answers
Help please!!!
katovenus [111]

Answer:

x = \frac{7+\sqrt{47}\times i }{4}

Step-by-step explanation:

<u>To solve quadratic systems,we always substitute one variable in terms if the other and then solve the equation.</u>

x + 2y = 6                                 ---------------(1)

y - 5 = (x-2)^{2}         ---------------(2)

y = (x-2)^{2} + 5         ---------------(3)

Substitute (3) in (1) ,

x + 2( (x-2)^{2} + 5 ) = 6

(a + b)^{2} =a^{2} + 2ab + b^{2}

x + 2( x^{2} - 4x + 4 + 5 ) = 6

2x^{2} - 7x + 12=0      --------------(4)

The roots of the quadratic equation ax^{2}  +bx+c is

x = \frac{(-b) + \sqrt{(-b)^{2}-4 \times ac }  }{2 \times a}  -----------(5)

According to equation (5),solution of (4) is

x =  \frac{7 + \sqrt{(-7)^{2}-4 \times 24 }  }{2 \times 2}

x =  \frac{7+\sqrt{49-96}}{4}

x = \frac{7+\sqrt{47}\times i }{4}

 

4 0
3 years ago
Solve for m: 5m - 9 = 4m + 2<br><br> 0<br><br> 11<br><br> 1<br><br> -7<br> WILL GIVE BRAINLIEST!
Tju [1.3M]

Answer:

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Step-by-step explanation:

5m - 9 = 4m + 2

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m = 11

8 0
2 years ago
What is the equation of a parabola with (−2, 4) as its focus and y = 6 as its directrix? Enter the equation in the box.
antiseptic1488 [7]

Check the picture below.  So the parabola looks more or less like so.

let's recall that the vertex is half-way between the focus point and the directrix, at "p" units away from both.

Let's notice that the focus point is below the directrix, that means the parabola is vertical, namely the squared variable is the "x", and it also means that it's opening downwards as  you see in the picture, namely that "p" is negative, in this case "p" is 1 unit, and thus is -1.

\bf \textit{parabola vertex form with focus point distance} \\\\ \begin{array}{llll} 4p(x- h)=(y- k)^2 \\\\ \stackrel{\textit{we'll use this one}}{4p(y- k)=(x- h)^2} \end{array} \qquad \begin{array}{llll} vertex\ ( h, k)\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=-2\\ k=5\\ p=-1 \end{cases}\implies 4(-1)(y-5)=[x-(-2)]^2\implies -4(y-5)=(x+2)^2 \\\\\\ y-5=-\cfrac{1}{4}(x+2)^2\implies y=-\cfrac{1}{4}(x+2)^2+5

6 0
3 years ago
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