Write (x^2) ^4without exponents
1 answer:
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Answer:
- hexahedron: triangle or quadrilateral or pentagon
- icosahedron: quadrilateral or pentagon
Step-by-step explanation:
<u>Hexahedron</u>
A hexahedron has 6 faces. A <em>regular</em> hexahedron is a cube. 3 square faces meet at each vertex.
If the hexahedron is not regular, depending on how those faces are arranged, a slice near a vertex may intersect 3, 4, or 5 faces. The first attachment shows 3- and 4-edges meeting at a vertex. If those two vertices were merged, then there would be 5 edges meeting at the vertex of the resulting pentagonal pyramid.
A slice near a vertex may create a triangle, quadrilateral, or pentagon.
<u>Icosahedron</u>
An icosahedron has 20 faces. The faces of a <em>regular</em> icosahedron are all equilateral triangles. 5 triangles meet at each vertex.
If the icosahedron is not regular, depending on how the faces are arranged, a slice near the vertex may intersect from 3 to 19 faces.
A slice near a vertex may create a polygon of 3 to 19 sides..
a=4 , b=3 These values make the equation true .
<u>Step-by-step explanation:</u>
Here we have , If a and b are both integers and b does not equal 0, then -(a/b) = (-a)/b = a/(-b) Choose two values for a and b. We need to find if those values make the equation true . Let's find out:
We have the following equation:
-(a/b) = (-a)/b = a/(-b) , Let a=4 , b=3 , So
⇒
⇒
⇒
⇒ { Multiplying by -1 }
⇒
Therefore , These values make the equation true .
We could solve for 'x' in the 2nd equation and then plug that into the first equation for 'x' and solve for 'y':
Subtract 6y to both sides:
Divide -2 to both sides:
Plug in 3y + 17 for 'x' in the first equation:
Distribute 5:
Combine like terms:
Subtract 85 to both sides:
Divide 17 to both sides:
This is the y-coordinate of the solution.