Vat=13% Discount=20% Sp with vat=20340 Mp=? Vat amount=?

A rectangular floor is 12 ft wide and 18 ft long. How much will it cost to carpet the floor if the carpet costs $1.39 per square

Oliga [24]

It will cost 300.24$ =12*18*1.39

4 0

3 years ago

What are three different ways to write 15,638

AlladinOne [14]

1. Fifteen thousand six hundred and thirty eight

5 0

3 years ago

Jane is is charge of making a banner for the basketball game this Saturday. She measures how long the banner is before painting

RSB [31]

Answer:

The measurement which Jane finds to be 10 meters is the length of the banner.

Step-by-step explanation:

The measurement of 10 meters which Jane found after measuring how long the banner is before painting is the LENGTH of the banner.

This is clear from the unit of what she finds (meters). It only indicates the measurement of one part of the banner, even though a banner has two parts, the length and width.

It is possible to find the AREA, or PERIMETER, or LENGTH.

But what she finds is the LENGTH of the banner. If it was Area or Perimeter, the unit would have been square meters.

7 0

3 years ago

What is the simplified form of (2 X 102)2 in standard notation? Do not use commas in your answer. (HAS TO BE A NUMBER)

Oxana [17]

Answer:

40000

Step-by-step explanation:

$(2 \times {10}^{2} )^{2} \\ = {2}^{2} \times {10}^{2 \times 2} \\ = 4 \times {10}^{4} \\ = 40000$

7 0

4 years ago

18. A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x, is found to be

avanturin [10]

Answer:

a. =50 ± 4.67

b. =50 ± 4.81

decreasing the sample size increase the margin of error

c. =50 ± 3.51

decreasing the confidence level reduced the margin of error

d. No. because the confidence interval coefficient is gotten from the table of normal distribution of Z value. therefore the confidence interval is only used for normal distributed population

Step-by-step explanation:

given

The sample mean, x, = 50,

the sample standard deviation, s, = 8.

a. Construct a 98% confidence interval for m if the sample size, n, is 20

for a 98% confidence interval of an inﬁnite population, thus for a sample of size N and mean x, drawn from an inﬁnite population having a standard deviation of σ, the mean value of the population is estimated to by:

x± 2.33σ /√N

for a conﬁdence level of 98%, Zc = 2.33 gotten from the table of confidence interval.

This indicates that the mean value of the population lies between

50- ( 2.33*8 /√20) and 50+ ( 2.33*8 /√20)

with 98% conﬁdence in this prediction.

=50 ± 4.67

=45.33 or 54.67

(b) Construct a 98% confidence interval for m if the sample size, n, is 15.

using the same method as above

x± 2.33σ /√N

This indicates that the mean value of the population lies between

50- ( 2.33*8 /√15) and 50+ ( 2.33*8 /√15)

=50 ± 4.81

=45.19 or 54.81

decreasing the sample size increase the margin of error

(c) Construct a 95% confidence interval for m if the sample size, n, is 20. Compare the results to those obtained in part

95% confidence interval =1.96 (gotten from table of confidence coefficient)

using x±1.96 σ /√N

This indicates that the mean value of the population lies between

50- (1.96 *8 /√20) and 50+ (1.96 *8 /√20)

=50 ± 3.51

=46.49 or 53.51

c. decreasing the confidence level reduced the margin of error

(d) Could we have computed the confidence intervals in parts (a)–(c) if the population had not been normally distributed?

No. because the confidence interval coefficient is gotten from the table of normal distribution of Z value. therefore the confidence interval is only used for normal distributed population

7 0

3 years ago