Chebyshev's inequality:
For a wide class of distributions, no more than

of the values can be outside of k standard deviations of the mean.
Here,
n = 16
μ = 2
σ = 1
range iin question = 0 to 4

=> k=2

meaning that at most 1/4 of the sample is outside the given range, or 3/4 of the sample= (3/4)*16 =12 is within the given range of 0 to 4 televisions.
Answer: at least 12 out of 16 households have between 0 to 4 televisions, according to the Chebyshev's inequality.
Answer:
x = 5
Step-by-step explanation:
Step 1: Write equation
5x - 7 = 18
Step 2: Solve for <em>x</em>
- Add 7 to both sides: 5x = 25
- Divide both sides by 5: x = 5
Step 3: Check
<em>Plug in x to verify it's a solution.</em>
5(5) - 7 = 18
25 - 7 = 18
18 = 18
4/7*3/1=12/7
answer is 12/7
Hello it’s 170 have a nice day
.25 • 13 = $3.25 (13 is the # of quarters)
$3.25+ 2(.10) = .20 (2 dimes)
$3.25+.20= $3.45