Answer:
- as written, -2
- with denominator parentheses, 0
- with f(x)=ln(x) and denominator parentheses, -1/2
Step-by-step explanation:
The problem as stated asks for the limit as x approaches 2 of (0/x) -2.
As written, the limit is (0/2) -2 = -2.
<u>Explanation</u>: f(x) is a constant, so the numerator is 0. The ratio 0/x -2 is defined as -2 everywhere except x=0. So, the value at x=2 is 0/2 -2 = -2.
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If you mean (f(2) -f(x))/(x -2), that limit is the limit of 0/(x-2) = 0 as x approaches 2.
<u>Explanation</u>: f(x) is a constant, so the numerator is 0. The ratio 0/(x-2) is zero everywhere except at x=2. The left limit and right limit are both 0 as x approaches 2. Since these limits agree, the limit is said to be 0.
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If you mean f(x) = ln(x) and you want the limit of (f(2) -f(x))/(x -2), that value will be -1/2.
<u>Explanation</u>: The value of the ratio is 0/0 at x=2, so we can find the limit using L'Hôpital's rule. Differentiating numerator and denominator, we have ...
lim = (-1/x)/(1)
The value is -1/2 at x=2.
I think the answer is 0.8 or 0.78.
You divide 140/180 which gives you 0.77777778
You can either round up to the nearest hundredth or tenth.
Answer:
-9 <= x <= 7
Step-by-step explanation:
Domain is the x, or independent variable. you just need to find how far x goes. First, you go to the veeery left and then go to the veeeery right of the plotted graph. Those 2 numbers are your domain.
Answer:
r = 144 units
Step-by-step explanation:
The given curve corresponds to a parametric function in which the Cartesian coordinates are written in terms of a parameter "t". In that sense, any change in x can also change in y owing to this direct relationship with "t". To find the length of the curve is useful the following expression;
In agreement with the given data from the exercise, the length of the curve is found in between two points, namely 0 < t < 16. In that case a=0 and b=16. The concept of the integral involves the sum of different areas at between the interval points, although this technique is powerful, it would be more convenient to use the integral notation written above.
Substituting the terms of the equation and the derivative of r´, as follows,
Doing the operations inside of the brackets the derivatives are:
1 ) 
2) 
Entering these values of the integral is
It is possible to factorize the quadratic function and the integral can reduced as,
Thus, evaluate from 0 to 16
The value is 
Answer:
92.40 is the answer for your question.
