Ask question

Ask question

All categories

borishaifa [10]

3 years ago

7

Find+the+z-scores+that+separate+the+middle+69%+of+the+distribution+from+the+area+in+the+tails+of+the+standard+normal+distributio

n

1 answer:

Tatiana [17]3 years ago

4 0

Answer and Explanation:

1 - 0.69/ 2 = 0.155

0.155 = -1.02

(-1.02, 1.02) = z

You might be interested in

There are 180 days in school year and you get 3 assignments per day. How many total assignments do you get in 1 school year

m_a_m_a [10]

Answer:

260 assignments in a school year

Step by Step:

There are 180 days in a school year and you do 3 assignments per day you multiple 180 and 3

6 0

3 years ago

a student has $1500 to deposit in a savings account. what is the lowest rate that would allow the student to earn $95 in simple

nika2105 [10]

rate = interest / principal

rate = 95/ 1500 = 0.0633333

rate = 6.33%

8 0

3 years ago

Read 2 more answers

Find the exact value of sin (arccos (3/5)). For full credit, explain your reasoning.

zloy xaker [14]

The equation for cosine is <span><span><span>cos<span>(x)</span></span>=<span>Adjacent/Hypotenuse
</span></span></span>The inside trig function is <span><span>arccos<span>(<span>3/5</span>)</span></span></span>, which means <span><span><span>cos<span>(x)</span></span>=<span>3/5</span></span></span>. Comparing <span><span><span>cos<span>(x)</span></span>=<span>Adjacent/Hypotenuse</span></span></span> with <span><span><span>cos<span>(x)</span></span>=<span>3/5
</span></span></span>
Find <span><span>Adjacent=3</span></span> and <span><span>Hypotenuse=5.
</span></span>Then, using the Pythagorean theorem, find <span><span>Opposite=?
</span></span>a² = c² - b²
a² = 5² - 3² = 25 - 9 = 16
a = √16 = 4

<span><span>Adjacent=3</span></span><span><span>Opposite=4</span></span><span><span>Hypotenuse=5
</span></span><span>
Plug in the value for sin(x) = opposite/hypotenuse

sin(x) = 4/5 </span>

6 0

3 years ago

What is the solution set of the equation 3x^2-34x-24=0?

scoray [572]

X= 6/17or the alternative form is 0.352941

7 0

3 years ago

Marcos had 15 coins in nickels and quarters. He had 3 more quarters than nickels. He wrote a system of equations to represent th

hodyreva [135]

Answer:

There are 6 coins in nickels and 9 coins in quarters.

Step-by-step explanation:

Now, to find the solution.

According to question:

The number of nickels = $x$ .

The number of quarters = $y.$

So, the total number of coins:

$x+y=15.$

He had 3 more quarters than nickels.

Thus,

$y=x+3$ .....(1)

Now, to get the solution:

$x+y=15$

Substituting the equation (1):

$x+(x+3)=15$

$x+x+3=15$

$2x+3=15$

<em>Subtracting both sides by 3 we get:</em>

<em /> $2x=12$ <em />

<em>Dividing both sides by 2 we get:</em>

$x=6.$

<em>The number of nickels = 6.</em>

Now, substituting the value of $x$ in equation (1):

$y=x+3\\\\y=6+3\\\\y=9.$

<em>The number of quarters = 9.</em>

Thus, there are 6 coins in nickels and 9 coins in quarters.

6 0

3 years ago