Answer:
3(2x^2-3x+14)
Step-by-step explanation:
6x^2-9x+42
All three terms have a common factor of 3
3(2x^2-3x+14)
Now let's focus on 2x^2-3x+14 and bring down the factor 3 later
so a=2
b=-3
c=14
Let's try to find two factors for ac that multiply to be a*c and add up to be b.
ac=28
b=-3
-----
ac=7(4)=14(2)=8(2)
Even if I made these pairs with both negatives nothing would give me -3
So you can only go as far as 3(2x^2-3x+14)
Here is another thing to help you if you have ax^2+bx+c and b^2-4ac<0 then it can't be factored (over reals)
Answer:
Step-by-step explanation:
Given:
Cost of L = $5
Cost of S = $3
No. of drinks sold = 60 drinks
Total sale = $220
Solution:
L + S = 60 - (1) (multiplying by 3)
5L + 3S = 220 - (2)
(-)3L +(-) 3S = (-)180 - (1)
2L = 40
L = 40 / 2
L = 20 Large drinks
20 + S = 60
S = 60 - 20
S = 40 small drinks
Therefore, 20 large drinks and 40 small drinks
PLEASE MARK ME AS BRAINLIEST
The answer to this would be C because you can multiply everything by 3 and still have a consistent-dependent system.
Answer:
Step-by-step explanation:
4x+6+3x+8=28
combine like terms
7x+14=28
subtract 14
7x=14
divide
x=2
if you plug it in you get-
4(2)+6+3(2)+8=
8+6+6+8=12+16=28
thats how you can check. if you want me to explain more i can totally help