Answer:
Six electrons are transferred in the formation of Al₂O₃.
Explanation:
Aluminium metal and Oxygen react to form Al₂O₃ as,
2 Al + 3/2 O₂ → Al₂O₃
Oxidation number of Al on left hand side is zero, while than on right hand side in Al₂O₃ is +3. Means it has lost 3 electrons per one atom and six electrons per two atoms. Also, the oxidation number of O at left hand side in O₂ is zero, while that in Al₂O₃ it is -2 per atom and -6 per 3 atoms.
So, two Al atoms have lost 6 electrons and 3 O atoms have gained six electrons.
No 11) one mole of Zn and two mole of HCL to get one mole of ZnCl and one mole of H2.
no 12) one mole of Mg and two mole of AgNO3 to get one mole of Mg(No3)2 and two mole of Ag.
no 13) one mole of CaCl2 and two mole AgNO3 to get two mole of AgCl and one mole of Ca(NO3)2.
no 14) two mole of Na3PO4 and three mole of BaCL2 to get one mole of Ba3(PO4)2 and six mole of NaCl.
no 15) two mole of NH4Cl and one mole of Ba(OH)2 to get one mole of BaCL2,two mole of NH3 and two mole of H2O.(am not much sure about this).
no 16) one mole of Na2CO3 and two mole of HCL to get two mole of NaCl,one mole of H2O and one mole of CO2.
no 17) one mole of K3PO4 and three mole of AgNO3 to get three mole of KNO3 and one mole of AgPO4.
Answer:
Possible lowest volume = 0.19 cm
Possible highest volume = 0.21 cm
Explanation:
Given Data
uncertainty = 0.01 cm
total volume = 0.20 cm
Possible lowest volume = ?
Possible highest volume = ?
Solution:
Possible lowest volume = total volume - uncertainty
Possible lowest volume = 0.20 cm - 0.01 cm
Possible lowest volume = 0.19 cm
Possible highest volume = total volume + uncertainty
Possible highest volume = 0.20 cm - 0.01 cm
Possible highest volume = 0.21 cm
Answer:
1.08 grams of nitrogen
Explanation:
Thermally ammonium perchlorate dissociate as shown in figure.
Thus as per equation two moles of ammonium perchlorate will give four moles of water, two moles of oxygen, one mole of chlorine and one mole of nitrogen,
The molar mass of ammonium perchlorate = 117.5g/mol
Two moles of ammonium perchlorate = 2X 117.5 = 234 g
The molar mass of nitrogen = 28g
thus 234 grams of ammonium perchlorate will give 28 grams of nitrogen
Hence 9 grams of ammonium perchlorate will give 1.08 grams of nitrogen
