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Slav-nsk [51]
3 years ago
10

What’s the percent composition of BaCrO4

Chemistry
1 answer:
Kay [80]3 years ago
6 0
The percent composition for chromium in BaCrO4, is 20.52 percent
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What is the difference between an enthalpy driven reaction and entropy driven reaction?
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<span>Enthalpy is regarding the amount of heat that is given off or taken in during the process of a reaction, while entropy is about the disorderliness of a reaction. 
Both are related in the equation ∆G=∆H-T∆S, where ∆G is the Gibbs free energy. So we can say that a reaction is both enthalpy and entropy driven. It's like, both of them are interlinked with each other. </span>
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4 years ago
Identify reagents necessary to convert cyclohexane into 1,3-cylohexadiene: notice that the starting material has no leaving grou
Vinvika [58]
<span>1,3-cylohexadiene i synthesized starting from cyclohexane in following 4 steps.

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3 years ago
Give me an example of pedegriee
Nana76 [90]
The ability to roll your tongue is determined by the dominant gene.
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4 years ago
Cerium (IV) ions are strong oxidizing agents in acid ic solution, oxidizing arsenio us acid to arsen ic acid accor ding to the f
kirill [66]

Answer:

0.2042 M is the original concentration of Ce^{4+} (aq) in the titrating solution.

Explanation:

Mass of As_2O_3 = 0.217 g

Moles of As_2O_3=\frac{0.217 g}{198 g/mol}=0.001096 mol

1 mole of As_2O_3 have 2 mole of As  and 1 mole of H_3AsO_3 have 1 mole of As.

So, from 1 mole of As_2O_3 we will have 2 moles of H_3AsO_3

Then from 0.001096 mol of As_2O_3 :

2\times 0.001096 mol=0.002192 mol of H_3AsO_3

2Ce^{4+}(aq)+H_3AsO_3(aq)+3H_2O(l)\rightarrow 2Ce^{3+}(aq)+H_3AsO_4(aq)+2H^+(aq)

According to reaction, 1 mole of H_3AsO_3 reacts with 2 mole of cerium (IV) ions,then 0.002192 mol of

\frac{2}{1}\times 0.002192 mol=0.004384 mol of cerium (IV) ions.

Volume of the  acidic cerium{IV) sulfate = 21.47 ml =0.02147 L

1 mL = 0.001 L

concentration = \frac{Moles}{Volume(L)}

[Ce^{4+}]=\frac{0.004384 mol}{0.02147 L}=0.2042 M

0.2042 M is the original concentration of Ce^{4+} (aq) in the titrating solution.

8 0
3 years ago
Find the density of an object that has a mass of 5 kg and a<br> volume of 50 cm3.
iren2701 [21]
  • Mass=5kg=5000g
  • Volume=50cm^3

\\ \rm\longmapsto Density=\dfrac{Mass}{Volume}

\\ \rm\longmapsto Density=\dfrac{5000}{50}

\\ \rm\longmapsto Density=100g/cm^3

4 0
3 years ago
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