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omeli [17]
2 years ago
10

Plutonium-240 decays according to the function Q(t) = Qoe^-kt

Mathematics
1 answer:
LuckyWell [14K]2 years ago
5 0

Answer:

  9990 years

Step-by-step explanation:

The exponential function with given values filled in can be solved for the unknown using logarithms.

__

  Q(t) = 12 = 36e^(-0.00011t)

  1/3 = e^(-0.00011t) . . . . . . divide by 36

  ln(1/3) = -0.00011t . . . . . . take natural logs

  t = ln(1/3)/(-0.00011) . . . . divide by the coefficient of t

  t ≈ 9990 . . . years

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What is 60 -1 1/2 (8) 2 equal
sleet_krkn [62]

Answer:

Step-by-step explanation:

60 -1 1/2 (8) 2

= 60 - 3/2 (8)(2)

= 60 - 3(8)

= 60 - 24

= 36

5 0
3 years ago
I need help with this .
vaieri [72.5K]
I would be glad to help you! I will solve through 3 to get you started.

This is a very important concept, so it would be helpful if you learn it on your own.

C= 2* pi* r

1. The radius is 5 cm. 5 cm represents r in the equation.
C= 2* 3.14 (or pi)* 5 
Multiply it by using a calculator. 
My answer was 31.4.

Let's try the second one.
2. The diameter is 9. Have of the diameter is the radius. 
9/2= 4.5 
Plug it into the equation.
C= 2*3.14*4.5
I got 28.26

One more. 
Plug it into the equation.
C= 2*3.14*5.6
35.17 was my answer.

Make sure to add the end signs to you answer, ft, cm, meter, etc.

Let me know if you need more help.

Brainliest answer is always appreciated.
7 0
3 years ago
Given f(x) = 3x - 1 and g(x)= -x + 6, find f(-2) + g(5).<br> A. -6<br> B. 6<br> C. 8
marta [7]

Answer:

A. -6

Step-by-step explanation:

f(x)=3x-1\\\\

In order to find f(-2) we will plugin x=-2

f(-2) = 3(-2)-1\\f(-2)=(3\times(-2))-1\\f(-2)=-6-1

f(-2)=-7

g(x)=-x+6

In order to find g(5) we will plugin x=5

g(5)=-5+6

g(5)=1

f(-2)+g(5)\\=-7+1\\=-6

∴ f(-2)+g(5)=-6

5 0
3 years ago
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kirill [66]

Answer:

No

Step-by-step explanation:

20x2.5=50

51.79-50=1.79

therefore there isn't enough buckets for all the dirt.

4 0
3 years ago
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nataly862011 [7]
It is D because all the numbers range from 12 to 23, with no number being extremely low or high compared this range.
6 0
3 years ago
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