Answer:
The y-intercept is the point (0,-8)
see the attached figure
Step-by-step explanation:
we have
we know that
The y-intercept is the value of the function f(x) when the value of x is equal to zero
so
For x=0
therefore
The y-intercept is the point (0,-8)
see the attached figure to better understand the problem
in this equation y=4/3x+4
hope this helps
Answer:
D: 0 < y < 7
Step-by-step explanation:
The domain is the input (i.e. the x values)
The range is the output (i.e. the y values)
So for the range, look at the y-coordinates of the end points of the line: (-6, 0) and (9, 7) ⇒ 0 < y < 7
Answer:
Step-by-step explanation:
Given that,
f(3) = 2
f'(3) = 5.
We want to estimate f(2.85)
The linear approximation of "f" at "a" is one way of writing the equation of the tangent line at "a".
At x = a, y = f(a) and the slope of the tangent line is f'(a).
So, in point slope form, the tangent line has equation
y − f(a) = f'(a)(x − a)
The linearization solves for y by adding f(a) to both sides
f(x) = f(a) + f'(a)(x − a).
Given that,
f(3) = 2,
f'(3) = 5
a = 3, we want to find f(2.85)
x = 2.85
Therefore,
f(x) = f(a) + f'(a)(x − a)
f(2.85) = 2 + 5(2.85 - 3)
f(2.85) = 2 + 5×-0.15
f(2.85) = 2 - 0.75
f(2.85) = 1.25
