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GenaCL600 [577]
2 years ago
7

W = 4, x = 5, and y = 6

Mathematics
1 answer:
Luda [366]2 years ago
5 0

Answer:

28, 28, 34, 34

Step-by-step explanation:

8x - (6 + y)

8(5) - (6 + 6)

40-12

28

w ¾ + x²

4(¾) + 5²

3 + 25

28

y² - 0.5w

6² - 0.5(4)

36 - 2

34

w / 4 + 3(x + y)

4 / 4 + 3(5 + 6)

1 + 3(11)

34

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Please help!!! this is due tomorrow!!1!!11!!!1!
Ronch [10]

Answer: m<KHL = 37 degrees.

m<GHK = 53 degrees

Step-by-step explanation:

<CHD and <KHL are vertical angles. They are equal in measure. m<CHD is 37 degrees, so m<KHL is also 37 degrees.

Notice <GHL is a 90 degree angle (because the lines that form it are perpendicular) and <GHL is made up of two angles: <GHK and <KHL.

m<GHK + m<KHL (37) = m< GHL (90 degrees)

Subtract 37 from both sides.

m<GHK = 53 degrees

7 0
2 years ago
PLEASE HELP ASAP 50 POINTS AND BRAINLYEST
Ludmilka [50]

Answer:

Either x = 3, y = 2

or

(3,2) is your answer.

Step-by-step explanation:

2x +y = 8  (1)

y = - x+ 5  (2)

Put equation (2) into equation (1). Use the y value in (2) to go into the y value in (1).

2x - x+5 = 8       Combine the x values

x + 5 =  8            Subtract 5 from both sides

x + 5-5 = 8-5

x=3

Now go back to (2). Put x in for the value of -x. Watch the sign.

y = -3+ 5

y = 2

So the answer is (3,2)

5 0
3 years ago
PLEASE PLEASE PLEASE HELP ME
lubasha [3.4K]

Answer:

CE = 17

Step-by-step explanation:

∵ m∠D = 90

∵ DK ⊥ CE

∴ m∠KDE = m∠KCD⇒Complement angles to angle CDK

In the two Δ KDE and KCD:

∵ m∠KDE = m∠KCD

∵ m∠DKE = m∠CKD

∵ DK is a common side

∴ Δ KDE is similar to ΔKCD

∴ \frac{KD}{KC}=\frac{DE}{CD}=\frac{KE}{KD}

∵ DE : CD = 5 : 3

∴ \frac{KD}{KC}=\frac{5}{3}

∴ KD = 5/3 KC

∵ KE = KC + 8

∵ \frac{KE}{KD}=\frac{5}{3}

∴ \frac{KC+8}{\frac{5}{3}KC }=\frac{5}{3}

∴ KC + 8 = \frac{25}{9}KC

∴ \frac{25}{9}KC - KC=8

∴ \frac{16}{9}KC=8

∴ KC = (8 × 9) ÷ 16 = 4.5

∴ KE = 8 + 4.5 = 12.5

∴ CE = 12.5 + 4.5 = 17

7 0
3 years ago
How many 2/3's are in 4/5
zhannawk [14.2K]

Step-by-step explanation:

4/5 + 2/3 = 2215 = 1 715 ≅ 1.4666667. Spelled result in words is twenty-two fifteenths (or one and seven fifteenths).

5 0
2 years ago
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In a school, the ratio of musicians to athletes is 3 : 1. The number of musicians is how many times the number of athletes?  ANS
loris [4]

Answer:

The number of musicians in the school is 3 times the number of athletes

Step-by-step explanation:


7 0
3 years ago
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