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iragen [17]
2 years ago
9

In the equation, y=4x-1, what does the 4 mean? What does the -1 mean?

Mathematics
2 answers:
irina1246 [14]2 years ago
6 0

Answer:

The equation is written in slope-intercept (y = mx + b) form. Therefore, the '4' represents the slope of the line, and the '-1' represents the y-intercept.

liraira [26]2 years ago
4 0
4 is the slope and -1 is the y-intercept
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​<br><br> −2x+15y=−24<br> 2x+9y=24<br> ​<br><br> what do y and x equal?
Anika [276]
X=12 y=0
Hope this helps
5 0
3 years ago
Please help with this question
svetlana [45]

Answer:

Segment JK is a chord in circle H

Line LM is a secant to circle H

Step-by-step explanation:

* Lets revise some definition in the circle

- The radius of the circle is a line segment drawn from the center of  

 the circle to a point on the circumference of the circle

- The chord of a circle is a line segment whose endpoints lie on the

 circumference of the circle

- The secant is a line intersect the circle in two points

- The tangent is a line touch or intersect the circle in one point

* Now lets solve the problem

- In circle H

∵ JK is a segment in circle H

∵ Point J lies on the circumference of circle H

∵ Point K lies on the circumference of circle H

∴ Segment JK is a chord in circle H

∵ LM is a line

∵ LM intersect circle H in two points L and M

∴ Line LM is a secant to circle H

4 0
3 years ago
What does &gt; −2 indicate about the positions of and −2 on the number line?
Aloiza [94]
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6 0
4 years ago
Determine whether each point lies on the graph of the equation.(a) 2x - y - 3 = 0 (a) (1, 2)Yes, the point is on the graph.No, t
Neko [114]

Answer:

a) (1, 2) not on the graph.

b) (1, -1) is on the graph.

Step-by-step explanation:

Given the equation of the line as:

2x - y - 3 = 0

The points given are

a) (1, 2)

To determine whether it is on the graph of the line or not.

To do so, we can do 2 things:

1. Draw the graph and plot the point on the graph to check whether it is on the graph or not.

2. To put the point in the given equation of the line, whether the equation is satisfied or not.

For method 1: Kindly refer to the attached image of the line and point plotted.

Method 2:

Let us put x=1, y=2 in the Left Hand Side (LHS) of equation.

2\times 1 - 2 - 3\\\Rightarrow -3 \neq 0 , RHS

(1, 2) Not on the graph.

(b) (1, -1)

For method 1: Kindly refer to the attached image of the line and point plotted.

Method 2:

Let us put x=1, y=-1 in the Left Hand Side (LHS) of equation.

2\times 1 - (-1) - 3\\\Rightarrow 3-3 = 0 = RHS

(1, -1) is on the graph.

3 0
4 years ago
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