1 joule = 6,242e+18ev
20 joule = 20 joule *6,242e+18 ev/joule =1,248e+20 ev
1,248e+20 ev / (10 ev / photon) =1,248e+19 photons.
Answer:
m∠N = 32°
NQ = 106°
When finding inscribed angles like ∠N with the intercepted arc, the equation is ∠N=1/2MP. (Inscribed angles are always half the degree of the arc length.) Plug in the corresponding value to get ∠N=1/2(64) to get 32°. When finding the angle of the intercepted arc with inscribed angles like NQ, the equation is NQ=2(∠P). Plug in the corresponding value to get 2(53) to get 106°.
Step-by-step explanation:
2 + 3 × (8 + 53 ÷ 1)
we first work out the equation in the brackets
so...
(8 + 53 ÷ 1)
division comes first so we divide 53÷1 which is 1 so the equation looks like this:
(8+53)
we work this out and get
61
then we work the rest out
2 + 3 × <u>61</u>
multiplication comes first so...
3×61= 183
and
2+ 183= 185
Therefore 2 + 3 × (8 + 53 ÷ 1)= <u>185</u>
Hope this helped- have a good day bro cya)
This differs on what number you want to talk about. 1 is the hundreds, 8 is the tenths, 7 is the ones.
