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Lubov Fominskaja [6]
2 years ago
12

23 10. Construct a quadratic equation whose roots are 1 and 2.A 3X-3x + 2-0 B. 3 + 3x - 2-0 C 22 + 3x - 2.0 D 2 - 3x +2=0 E.2x -

3x - 2 =0​
Mathematics
1 answer:
Gre4nikov [31]2 years ago
5 0

Answer:

Step-by-step explanation:

Basic quadratic equation has this following form:

(x-x_{1})(x-x_{2})=0

where x1 and x2 are the roots.

For x_{1}=1 and x_{2}=2, we can find:

(x-1)(x-2)=0 \rightarrow x^{2}-2x-x+2=0 \rightarrow x^{2}-3x+2=0

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5 yrs ago, Nuri was thrice as old as Sonu. 10 yrs later, Nuri will be twice as old Sonu. How old are Nuri n Sonu?​
Papessa [141]

Answer:

Answer will be 50

Step-by-step explanation:

Let us suppose, present age of Nuri be ‘x’ years and present age of Sonu be ‘y’ years.

Now, it is given that five years ago, Nuri was thrice old as Sonu. Hence,

Five years ago,

Nuri’s age = x-5 years

Sonu’s age = y-5 years

And relation between ages can be given as

Nuri’s age = 3×sonu’s age or

x-5 = 3(y-5)

x-5 = 3y-15

x-3y+10 = 0 ………..(i)

Another relation is given in the problem that ten years later, Nuri is twice as old as Sonu.

So, ten years ago,

Nuri’s Age = x+10

Sonu’s Age = y+10

And relation between ages can be written as

x+10 = 2(y+10)

x+10 = 2y+20

x-2y-10 = 0 …………..(ii)

Now we can solve the equation (i) and (ii) to get values of x and ‘y’ or present ages of Nuri and Sonu.

Value of ‘x’ from equation (i) be

x = 3y-10 ……….(iii)

Putting value of ‘x’ from equation (iii) in equation (ii) we get,

3y-10-2y-10 = 0

y = 20

Now, from equation (iii) value of ’x’ can be given as,

x= 3(20)-10

x = 50

Hence, the present ages of Nuri and Sonu are 50 years and 20 years respectively.

7 0
2 years ago
ASAP! GIVING BRAINLIEST! Please read the question THEN answer correctly! No guessing. Show your work or give an explaination.
leonid [27]

Answer:

C. F(x) = 2(x-2)²+2

Step-by-step explanation:

This graph was changed by a vertical and horizontal shift because the graph moved over and up

  • A vertical shift would be when a constant is added to the output, resulting in the graph moving up or down: y = f(x) + k
  • A horizontal shift would be when a constant is added to the input, resulting in the graph moving left or right: y = f(x + h)

With this information we can determine how the graph was transformed

  • Looking at the graph, the origin is now at (2,2) instead of (0,0)
  • We can see that the graph moved to the right h units, indicating a horizontal shift 2 units to the right
  • We can also see that the graph moved up k units, indicating a vertical shift 2 units upward

Our equation for f(x) should be in the form y = a(x + h)² + k

  • Substituting in all our known values, we get the equation:
  • F(x) = 2(x-2)²+2
5 0
3 years ago
Whats the answer for (5x + 8)(4x² + 6x - 8)
mestny [16]
(5x + 8)(4x^2 + 6x - 8)\\ \\ 5x(4x^2 + 6x - 8) + 8(4x^2 + 6x - 8) \\ \\ 20x^3 + 30x^2 - 40x + 8(4x^2 + 6x - 8) \\ \\ 20x^3 + 30x^2 - 40x + 32x^2 + 48x - 64 \\ \\ 20x^3 + (30x^2 + 32x^2) + (-40x + 48x) - 64 \\ \\ 20x^3 + 62x^2 + 8x - 64 \\ \\

The final result is: 20x^3 + 62x^2 + 8x - 64.
4 0
3 years ago
Nancy and Karen went on a trip to the mountain. Nancy started her trip 30 minutes later than Karen. They started from the same p
Katyanochek1 [597]
Distance = (rate)(time)
In this problem, note that both girls traveled the same distance.

Karens distance = r * 1.5 hrs          we dont know her rate
Nancy distance = 50 * 1 hr              we know she started 30 min later
                                                         but arrived at the same time

since the distances are equal
r*1.5 = 50 * 1          all you have to do is solve for r

1.5r = 50
r = 50/1.5
r = 33 1/3 miles per hour
3 0
3 years ago
Jennifer $12 to spend on lunch and roller rink. Admission to the roller rink is $5.75 Jennifer estimates that she can buy a larg
den301095 [7]
She may or may not because it depends on how much is the food and drink
6 0
2 years ago
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