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Lubov Fominskaja [6]
2 years ago
12

23 10. Construct a quadratic equation whose roots are 1 and 2.A 3X-3x + 2-0 B. 3 + 3x - 2-0 C 22 + 3x - 2.0 D 2 - 3x +2=0 E.2x -

3x - 2 =0​
Mathematics
1 answer:
Gre4nikov [31]2 years ago
5 0

Answer:

Step-by-step explanation:

Basic quadratic equation has this following form:

(x-x_{1})(x-x_{2})=0

where x1 and x2 are the roots.

For x_{1}=1 and x_{2}=2, we can find:

(x-1)(x-2)=0 \rightarrow x^{2}-2x-x+2=0 \rightarrow x^{2}-3x+2=0

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Quadrilateral ABCD is inscribed in a circle with angle measures m∠A = (11x − 8)°, m∠B = (3x2 + 1)°, m∠C = (15x + 32)°, and m∠D =
dimulka [17.4K]

Answer:

No for all of the 4 values

Step-by-step explanation:

The sum of the internal angles of a quadrilateral is always 360°, so we have that:

m∠A + m∠B + m∠C + m∠D = 360

11x - 8 + 3x2 + 1 + 15x + 32 + 2x2 - 1 = 360

5x2 + 26x - 320 = 0

Solving the quadratic function using Bhaskara's formula, we have:

Delta = 26^2 + 4*5*320 = 7076

sqrt(Delta) = 84.12

x1 = (-26 + 84.12)/10 = 5.81

x2 = (-26 - 84.12)/10 = -11.01 (this value will generate negative angles, so it is not valid).

Now, finding the angles, we have:

m∠A = 11*5.81 - 8 = 55.91°

m∠B = 3*(5.81)^2 + 1 = 102.27­°

m∠C = 15*5.81 + 32 = 119.15°

m∠D = 2*(5.81)^2 - 1 = 66.51°

As all these values are different from the values shown, the answer is No for all of them.

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