Answer:
D |-11 | >-25
Step-by-step explanation:
|-11 | = 11
11 > -25
Alrighty
squaer base so length=width, nice
v=lwh
but in this case, l=w, so replace l with w
V=w²h
and volume is 32000
32000=w²h
the amount of materials is the surface area
note that there is no top
so
SA=LW+2H(L+W)
L=W so
SA=W²+2H(2W)
SA=W²+4HW
alrighty
we gots
SA=W²+4HW and
32000=W²H
we want to minimize the square foottage
get rid of one of the variables
32000=W²H
solve for H
32000/W²=H
subsitute
SA=W²+4WH
SA=W²+4W(32000/W²)
SA=W²+128000/W
take derivitive to find the minimum
dSA/dW=2W-128000/W²
where does it equal 0?
0=2W-1280000/W²
128000/W²=2W
128000=2W³
64000=W³
40=W
so sub back
32000/W²=H
32000/(40)²=H
32000/(1600)=H
20=H
the box is 20cm height and the width and length are 40cm
It is C. floor 20 and floor c have the same amount of tenants
Answer: a = -15
Step-by-step explanation:
3a + b = 9
b=54
3a + 54 = 9
3a = 9-54
3a= -45
<h3>
</h3>
- x + = -
<h2>a= -15</h2>
Hi Brielle the correct answer to your question is 3.12 x 4.0 = 12.48
