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ivanzaharov [21]
2 years ago
14

A company has recently been hiring new employees. Today the company has 29% more employees than it did a year ago. If there are

currently 38700 employees, how many employees did the company have a year ago?
Mathematics
1 answer:
mezya [45]2 years ago
5 0

Answer:

27477

Step-by-step explanation:

Subtract 38700 from 29% = 27477.

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A picture representing 24÷6
Licemer1 [7]

Answer:

4

Step-by-step explanation:

24÷6

6 x ? = 24

6 goes into 24 four times

24÷6=4




7 0
3 years ago
Read 2 more answers
Find the simple interest earned in a savings account that pays 5% interest if $500 is deposited for 4 years. A. $100, B. $1000,
g100num [7]
To calculate simple interest, you first need to multiply the original amount by the percentage of the money which is going to be added.

In this situation, 500 x 0.05 is the interest which will be added each year.
Therefore, $25 will be added each year. Since it is over 4 years, it is (25*4).
So the account will have earned $100 of simple interest.

Although the account will contain $600, it will have EARNED $100 of interest since it started with $500 already.

Answer - A $100 of simple interest will be earned.
3 0
4 years ago
Use the properties of logarithms to expand the following expression as much as possible. simplify any numerical expressions that
FinnZ [79.3K]
\bf log_{{  a}}(xy)\implies log_{{  a}}(x)+log_{{  a}}(y)
\\ \quad \\\\
% Logarithm of rationals
log_{{  a}}\left(  \frac{x}{y}\right)\implies log_{{  a}}(x)-log_{{  a}}(y)
\\ \quad \\\\
% Logarithm of exponentials
log_{{  a}}\left( x^{{  b}} \right)\implies {{  b}}\cdot  log_{{  a}}(x)\\\\
-----------------------------\\\\
ln\left( \cfrac{6x^9}{y^5} \right)\implies ln(6x^9)-ln(y^5)\implies ln(6)+ln(x^9)-ln(y^5)
\\\\\\
ln(6)+9ln(x)-5ln(y)
8 0
3 years ago
Plzzzzzzzzzzzs help me ​
d1i1m1o1n [39]

Answer:

Please post a picture with higher quality, I cannot read this one

Step-by-step explanation:

4 0
3 years ago
Solve tan 10 - tan 50 +tan 70 with trigonometry.
Jobisdone [24]
Below is the solution, I hope it helps.

  <span>i) tan(70) - tan(50) = tan(60 + 10) - tan(60 - 10) 

= {tan(60) + tan(10)}/{1 - tan(60)*tan(10)} - {tan(60) - tan(10)}/{1 + tan(10)*tan(60)} 

ii) Taking LCM & simplifying with applying tan(60) = √3, the above simplifies to: 

= 8*tan(10)/{1 - 3*tan²(10)} 

iii) So tan(70) - tan(50) + tan(10) = 8*tan(10)/{1 - 3*tan²(10)} + tan(10) 

= [8*tan(10) + tan(10) - 3*tan³(10)]/{1 - 3*tan²(10)} 

= [9*tan(10) - 3*tan³(10)]/{1 - 3*tan²(10)} 

= 3 [3*tan(10) - tan³(10)]/{1 - 3*tan²(10)} 

= 3*tan(30) = 3*(1/√3) = √3 [Proved] 

[Since tan(3A) = {3*tan(A) - tan³(A)}/{1 - 3*tan²(A)}, 
{3*tan(10) - tan³(10)}/{1 - 3*tan²(10)} = tan(3*10) = tan(30)]</span>
7 0
3 years ago
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