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ivanzaharov [21]
2 years ago
14

A company has recently been hiring new employees. Today the company has 29% more employees than it did a year ago. If there are

currently 38700 employees, how many employees did the company have a year ago?
Mathematics
1 answer:
mezya [45]2 years ago
5 0

Answer:

27477

Step-by-step explanation:

Subtract 38700 from 29% = 27477.

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Take out common factor, 3 :

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6 0
2 years ago
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yan [13]

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Step-by-step explanation:

8 0
2 years ago
Almost all companies utilize some type of year-end performance review for their employees. Human Resource (HR) at a university's
balu736 [363]

Answer:

The Answer is 76.

Step-by-step explanation:

Given the normal distribution " 10% of employees (rated) exemplary, 20% distinguished, 40% competent, 20% marginal, and 10% unacceptable'',  we can see that exemplary employees are top 10% rated employees.

We have the formula for normal distribution:

z=(X-M)÷σ

where z is the <em>minimum z-score </em>for top 10% employee, X is the <em>minimum </em>score for top 10% employee, M is the <em>mean</em> of the score distribution, σ is the <em>standard deviation</em> of the score distribution.

The z-score we are looking for is the value "a" that separates the highest 10% from the lowest 90% i.e. P(z≤a)=0.90

If we look at z-table, corresponding value for a is 1.28155

We can now put the values in the formula:

1.28155=\frac{X-50}{20}

So X=(1.28155×20)+50=75.631

Therefore minimum score for exemplary employee is 76.

3 0
2 years ago
Sam had $7.55 he then gave $4.46 to his friend. How much money does same have left?
Nana76 [90]

answer:

$3.09 left over

7 0
3 years ago
Solve pls brainliest
Murrr4er [49]

Answer:

-1, -24

Step-by-step explanation:

-9-(-8)

double negative = positive

-9+8=-1

21-45=-24

6 0
2 years ago
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