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Daniel [21]
3 years ago
14

A researcher developing scanners to search for hidden weapons at airports has concluded that a new scanner is significantly bett

er than the current scanner. He made his decision based on a test using alpha equals 0.025 . Would he have made the same decision at alpha equals 0.10 question mark How about alpha equals 0.005 question mark Explain.
Mathematics
1 answer:
CaHeK987 [17]3 years ago
3 0

Step-by-step explanation:

Since the decision is made on the test based on the use of alpha equals 0.025, the p-value of the test would have been higher than the level of significance provided that is 0.025 since the test is not important.

p > 0.025

Now if we know that p > 0.025, this would not necessarily mean that p > 0.1 also, therefore we do not know with the given information that he would have made the same decision for 0.1 level of significance, ( we are not sure about his decision in that case ).

Now for the level of significance of 0.005, we would be sure that p > 0.005 as it is greater than 0.025, therefore the test is not significant at this level of significance as well. Therefore he would have made the same decision for 0.005 level of significance.

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Is anyone able to figure this out, I can't do this
katrin [286]

Answer:

C. √2 - 1

Step-by-step explanation:

If we draw a square from the center of the large circle to the center of one of the small circles, we can see that the sides of the square are equal to the radius of the small circle (see attached diagram)

Let r = the radius of the small circle

Using Pythagoras' Theorem a^2+b^2=c^2

(where a and b are the legs, and c is the hypotenuse, of a right triangle)

to find the diagonal of the square:

\implies r^2 + r^2 = c^2

\implies 2r^2 = c^2

\implies c=\sqrt{2r^2}

So the diagonal of the square = \sqrt{2r^2}

We are told that the radius of the large circle is 1:

⇒ Diagonal of square + r = 1

\implies \sqrt{2r^2}+r=1

\implies \sqrt{2r^2}=1-r

\implies 2r^2=(1-r)^2

\implies 2r^2=1-2r+r^2

\implies r^2+2r-1=0

Using the quadratic formula to calculate r:

\implies r=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

\implies r=\dfrac{-2\pm\sqrt{2^2-4(1)(-1)}}{2(1)}

\implies r=\dfrac{-2\pm\sqrt{8}}{2}

\implies r=-1\pm\sqrt{2}

As distance is positive, r=-1+\sqrt{2}=\sqrt{2}-1  only

5 0
3 years ago
Read 2 more answers
I need help with my homework… plz
ValentinkaMS [17]
Which one do you need help on
3 0
2 years ago
Mabel has read 3/4 of a book, or 390 pages. How many pages are in the entire book?
Arte-miy333 [17]
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Picking both would be 1/4 x 13/51 = 13/204

The answer is C.

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3 years ago
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Answer: b

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