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42 I 3,452
82 with a remainder
There are <u>82</u> integers between 14 and 2452 that can be divided with a remainder of 0
Answer:
9pr = 2q^2
Step-by-step explanation:
28.
px^2 + qx + r = 0
If one root is A then the other root is 2A
We have A + 2A = -q/p and A*2A = r/p
So 3A = -q/p so A = -q/3p and A^2 = r/2p so A = √ (r / 2p)
Equating these 2 equations:-
-q/3p = √(r / 2p)
q^2 / 9p^2 = r / 2p
9p^2r = 2pq^2
9pr = 2q^2 (answer)
Answer:
B
Step-by-step explanation:
plz give brainliest i have never got it
Answer:
I think 100$
Step-by-step explanation:
I can't be to sure
Answer:
161,084,000
Step-by-step explanation:
7 x 11,506,000 = 80,542,000
80,542,000 x 2 = 161,084,000